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katrin2010 [14]
3 years ago
9

What element has an r.m.m of 72​

Chemistry
1 answer:
igomit [66]3 years ago
7 0

Answer:

Germanium

Explanation:

The element Germanium is one with a relative molecular mass of 72. This corresponds to the mass number of this element.

Relative molecular mass of an element is the mass of a formula unit to that of a carbon-12 atom.

The chemical symbol of Germanium is Ge. It is a lustrous and hard metalloid belonging to the carbon group.

It was discovered by Clemens Alexander Winkler.

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My Everest is the highest mountain on earth.its height is 8.848 km. Convert this height to feet. Write your answer in standard n
Vinvika [58]

Answer: 2.9(10)^{7} ft

Explanation:

Firstly we need to know that 1 km=3280.84 ft, then we cam make the conversion:

8848 km \frac{3280.84 ft}{1 km}=29,028,872.32 ft This is the height of Mount Everest in feet

However, we can express it using scientific notation by counting to the left the decimal spaces:

29,028,872.32 ft \approx 2.9(10)^{7} ft

3 0
3 years ago
What type of organic compound has the empirical formula CH2O and can serve as energy storage or the starting material for fats a
Luda [366]
Carbohydrates. CH2O is the most basic formula of simple sugars.Empirical formula is the lowest whole number ratio of atoms in a formula.For example glucose is C6H12O6 can be reduced by 6 to get CH2O. Simples sugars include glucose and fructose which can serve as sources of energy for fats and amino acids.
4 0
3 years ago
Please help fast, I will give brainliest.
Serga [27]

Answer:

B

Explanation:

7 0
2 years ago
Read 2 more answers
If you burn 48.6 g of hydrogen and produce 434 g of water, how much oxygen reacted?
GarryVolchara [31]

Answer:

            385.69 g of O₂

Solution:

The Balance Chemical equation for said reaction is as follow;

                                       2 H₂  +  O₂    →   2 H₂O

According to Equation,

        4.032 g ( 2 mol) H₂ reacts to produce  =  36.03 g (2 mol) of H₂O

So,

        48.6 g H₂ on reaction will produce  =  X g of H₂O

Solving for X,

                     X =  (48.6 g × 36.03 g) ÷ 4.032 g

                     X  =  434.29 g of H₂O

It means that the H₂ provided is in Excess. Therefore, the yield of product (H₂O) is being controlled by O₂ (Limiting Reagent).

So, According to Equation,

                    36.03 g (2 mol) H₂O is produced by  =  31.998 g (1 mol) of O₂

So,

                434.29 g of H₂O will be produced by  =  X g of O₂

Solving for X,

                     X =  (434.29 g × 31.998 g) ÷ 36.03 g

                    X  =  385.69 g of O₂

8 0
2 years ago
When titrating 50.0 mL of 0.10 M H2SO4 with 0.10 M NaOH, how many mL of NaOH will you have added to reach the 1st equivalence po
Keith_Richards [23]

Answer:

50.0mL 0.10M NaOH

Explanation:

The chemical equation of H₂SO₄ with NaOH to reach the first equivalence point is:

H₂SO₄ + NaOH → HSO₄⁻ + Na⁺ + H₂O

<em>Where 1 mole of the H₂SO₄ reacts per mole of NaOH</em>

<em />

The initial moles of H₂SO₄ are:

50.0mL = 0.0500L × (0.10 mol / L) = 0.0050 moles of H₂SO₄

As 1 mole of the acid reacts per mole of NaOH, to reach the first equivalence point we need to add 0.0050 moles of NaOH. As molarity of NaOH is 0.10M, the volume that we need to add to reach 1st equivalence point is:

0.0050 moles NaOH ₓ (1L / 0.10 moles NaOH) = 0.050L NaOH 0.10M =

<h3>50.0mL 0.10M NaOH</h3>
5 0
3 years ago
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