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Leviafan [203]
4 years ago
15

1 Ca (s) + 2 HF (aq) → 1 CaF2 (s) +1 H2 (g) Identify the coefficient(s). Identify the subscript(s). What is the state of each of

the reactants? What will serve as evidence that a reaction has occurred?
Chemistry
1 answer:
blagie [28]4 years ago
6 0

Answer :

The coefficients are, 1 in Ca, 2 in HF, 1 in CaF₂ and 1 in H₂

The subscripts are, 2 in CaF₂ and 2 in H₂

The states of reactants are, Ca in solid state (s) and HF in aqueous state (aq).

The evidence that a reaction occurred is, the new substances are formed in the chemical reaction.

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

If the amount of atoms of each type on the left and right sides of a reaction differs then to balance the equation by adding coefficient in the front of the elements or molecule or compound in the chemical equation.

The coefficient tell us about that how many molecules or atoms present in the chemical equation.

Coefficient : It is a number that written in front of the element, molecule or ion.

Subscript : It is a small number that placed slightly lower-right than the normal text.

The given balanced chemical reaction is:

1Ca(s)+2HF(aq)\rightarrow 1CaF_2(s)+1H_2(g)

In this reaction:

The coefficients are, 1 in Ca, 2 in HF, 1 in CaF₂ and 1 in H₂

The subscripts are, 2 in CaF₂ and 2 in H₂

The states of reactants are, Ca in solid state (s) and HF in aqueous state (aq).

The evidence that a reaction occurred is, the new substances are formed in the chemical reaction.

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What information is needed to determine a molecular formula
Gnom [1K]

Answer:

Empirical formulas can be determined from the percent composition of a compound. In order to determine its molecular formula, it is necessary to know the molar mass of the compound. Chemists use an instrument called a mass spectrometer to determine the molar mass of compounds.

6 0
3 years ago
Read 2 more answers
PLEASE HELP! How does one determine how much of a molecule is produced in a reaction?
kozerog [31]
I believe the answer is C !
7 0
4 years ago
What is the pH of an aqueous solution of HCl with a hydrogen ion
yulyashka [42]

Answer:

pH = 5.17

Explanation:

pH = -log[H+] = -log(6.7 x 10^-6) = 5.17

6 0
3 years ago
metal weighing 6.98 g was heated to 91.29 °C and then put it into 114.84 mL of water (initially at 24.37 °C). The metal and wate
torisob [31]

Answer:

The specific heat of the metal is 10.93 J/g°C.

Explanation:

Given,

For Metal sample,

mass = 6.98 grams

T = 91.29°C

For Water sample,

volume = 114.84 mL

T = 24.37°C.

Final temperature of mixture = 33.54°C.

When the metal sample and water sample are mixed,

The addition of metal increases the temperature of the water, as the metal is at higher temperature, and the  addition of water decreases the temperature of metal. Therefore, heat lost by metal is equal to the heat gained by water.

Since, heat lost by metal is equal to the heat gained by water,

Qlost = Qgain

However,

Q = (mass) (ΔT) (Cp)

(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)

After mixing both samples, their temperature changes to 27°C.

It implies that

water sample temperature changed from  24.37°C to 33.54°C and metal sample temperature changed from 91.29°C to 33.54°C.

We have all values, but, here mass of water is not given. It can be found by using the formula

Density = Mass/Volume

Since, density of water = 1 g/mL

we get, Mass = 114.84 grams.

Since specific heat of water is 4.184 J/g°C.

Now substituting all values in (mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)

(6.98)(91.29 - 33.54)(Cp) = (114.84)(33.54 - 24.37)(4.184)

solving, we get,

Cp = 10.93 J/g°C.

the specific heat of the metal is 10.93 J/g°C.

7 0
3 years ago
A sample of pure NO2 is heated to 335 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+
vodka [1.7K]

The equilibrium constant for the reaction is 0.00662

Explanation:

The balanced chemical equation is :

2NO2(g)⇌2NO(g)+O2(g

At t=t  1-2x ⇔ 2x + x moles

The ideal gas law equation will be used here

PV=nRT

here n= \frac{w}{W} = \frac{w}{V}= density

P = \frac{density RT}{M}       density is 0.525g/L, temperature= 608.15 K, P = 0.750 atm

putting the values in reaction

0.75 = \frac{0.525 x 0.0821 x 608.15 }{M}

  M    = 34.61

         

to calculate the Kc

Kc=\frac{ [NO] [O2]}{NO2}

  \frac{1-2x}{1+x} x M NO2 + \frac{2x}{1+x} M NO+ \frac{x}{1+x} M O2

Putting the values as molecular weight of NO2, NO,O2

\frac{46(1-2x) +30(2x)+32x}{1+x}

34.61= \frac{46}{1+x}

x= 0.33

Kc= \frac{4x^2)x}{1-2x^2}

    putting the values in the above equation

Kc = 0.00662

     

5 0
3 years ago
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