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Sphinxa [80]
2 years ago
13

How many moles are in 12.0 grams of O2

Chemistry
1 answer:
horrorfan [7]2 years ago
5 0

Answer:

Moles = 0.375

Explanation:

Moles= m/M

= 12/32 = 0.375mol

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Arrange the following in order of size, from smallest to largest: polymer, monomer, carbon atom,
densk [106]
We can arrange the following entities from sizes smallest to largest in: <span><span>
1.                                 </span>Carbon atom. Consider the carbon atom in the periodic table which evidently small in size. Like any other atom such as hydrogen and oxygen.</span> <span><span>
2.                                 </span>Monomer. Is a singular molecule that can combine itself with elongated chains and other molecules. And thus form,</span>
<span><span>3.                                 </span>Polymer. Polymers are made from a complex amalgamation of monomers.</span>
<span><span>4.                                 </span>Macromolecule. And thus the macromolecules from the word macro are the biggest component. Which forms the lipid, proteins, RNA enzymes in the cell. <span>

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8 0
3 years ago
(b) Which solution has a higher percent ionization of the acid, a 0.10M solution of HC2H3O2(aq) or a 0.010M solution of HC2H3O2(
boyakko [2]

Answer: The percent ionization is higher for 0.010 M solution of HC_2H_3O_2

Explanation:

HC_2H_3O_2\rightarrow H^+C_2H_3O_2^-

 cM           0M           0M

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

a) Given c= 0.10 M and \alpha = ?

K_a=1.8\times 10^{-5}

Putting in the values we get:

1.8\times 10^{-5}=\frac{(0.10\times \alpha)^2}{(0.10-0.10\times \alpha)}

(\alpha)=0.013

\%(\alpha)=0.013\times 100=1.3\%

b) Given c= 0.010 M and \alpha = ?

K_a=1.8\times 10^{-5}

Putting in the values we get:

1.8\times 10^{-5}=\frac{(0.010\times \alpha)^2}{(0.010-0.010\times \alpha)}

(\alpha)=0.041

\%(\alpha)=0.041\times 100=4.1\%

The percent ionization is higher for 0.010 M solution of HC_2H_3O_2

6 0
3 years ago
How many moles of AlCl3 are in 2.25L of a 0.15 molar solution?
Darya [45]

Answer:

Option C. 0.34 moles

Explanation:

Data obtained from the question include:

Molarity = 0.15M

Volume = 2.25L

Mole =

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.15 x 2.25

Mole = 0.34mole

The number of mole of AlCl3 present in the solution is 0.34mole.

5 0
3 years ago
DESCRIBE TROPICAL STORM; THUNDERSTORM; AND TORNADOES
Sergeu [11.5K]

Answer:

a tropical strom is when theres a lot of rain and it almost developed into a hurricane and a thunderstorm is rain with lightning and thunder but not that bad like a tropical storm and a tornado is when there is a huge gust of win that is formed in a circle like shape and could cause damage to homes

Explanation:

7 0
2 years ago
A sample of oxygen gas in one container has a volume of 20.0mililiter at 297 K and 101.3 kPa. The entire sample is transferred t
VashaNatasha [74]

Answer: V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{P_1V_1T_2}{T_1P_2}

where,

P_1 = initial pressure of gas = 101.3 kPa

P_2 = final pressure of gas = 94.6 kPa

V_1 = initial volume of gas = 20.0 ml

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 297K

T_2 = final temperature of gas = 283K

Now put all the given values in the above equation, we get the final volume of gas.

V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

V_2=20.4ml

Thus the correct numerical setup for calculating the new volume is \frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

3 0
3 years ago
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