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laila [671]
3 years ago
9

How fast must a 6 kg cat run to have kinetic energy of 150 j?

Physics
1 answer:
morpeh [17]3 years ago
3 0
KE = 0.5mv^2
150 = 0.5*6*v^2
v^2 = 50
v = 7.1m/s
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Answer:

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P=\dfrac{F\cos\theta \times s}{t}

P=\dfrac{F\cos\theta\times 2\pi r}{t}

Here, \theta=0^{\circ}

Where, F = force

t = time

r = radius

Put the value into the formula

P=\dfrac{29\cos0\times2\pi\times0.27}{1.9}

P=15.26\ W

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