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FromTheMoon [43]
3 years ago
6

What is the frequency of a wave travelling at 45.45 m/s with a wavelength of 2 m?

Physics
1 answer:
HACTEHA [7]3 years ago
4 0

Answer:

22.73 Hz

Explanation:

Frequency = 45.45/2 = 22.73 Hz

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Type in the correct values to correctly represent the valence electron configuration of oxygen: AsB2pC A = B = C = What is the c
vitfil [10]

Explanation:

Oxygen has an atomic number of 8 with 2 electrons in its innermost shell (s orbital) and 6 remaining electrons in its outermost shell.

The electronic configuration of the oxygen element will therefore be expressed as;

1s²2s²2p⁴

Since we are to find the valence electron configuration of oxygen, this means we are going to consider only electrons in the outermost shell. The outermost shell of oxygen only contains 6electrons. The electronic configuration will be;

2s²2p⁴ (ignoring the innermost electrons)

Comparing with As^B2p^C

we will have;

As^B = 2s²

A = 2, B = 2

2p^C = 2p⁴

p^c = p⁴

C = 4

Hence A = 2, B = 2 and C = 4

The oxygen ion is represented as O₂²⁻. Therefore the charge of an oxygen ion is -2

5 0
3 years ago
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Determine the Reynolds number for a flow of 0.2 m^3/s through a 203 mm inner diameter circular pipe of a fluid with rho=680 kg/m
IrinaK [193]

To find a solution to this problem it is necessary to apply the concepts related to the Reynolds number and its definitions on the type of fluid.

A Reynolds number less than 2000 considers the laminar fluid, while a Reynolds number greater than 4000 is considered a turbulent fluid. (The intermediate between the two values would be a transient fluid)

The mathematical equation that defines the Reynolds number is given by

Re = \frac{\rho V D}{\mu}

Where

\rho = Density

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D= Diameter

\mu = Viscosity

Our values are given as

Q = 0.2m^3/s

D = 203*10^{-3}m

\rho = 680kg/m^3

\mu = 3.1*10^{-4}Ns/m^2

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Q = VA

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V = Velocity

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Replacing,

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Replacing at the Reynolds equation,

Re = \frac{\rho VD}{\mu}

Re = \frac{680*3.08*203*10^{-3}}{3.1*10^{-4}}

Re = 1.37*10^6

Since Reynolds' number is greater than 4000, then we consider this a turbulent fluid.

3 0
3 years ago
An object is weighed at different locations on the
Step2247 [10]

Answer:

C

Explanation:

The weight will always be different while mass is described as the stuff inside an object, and that stays the same.

Such as it weighs differently in space.

6 0
2 years ago
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cupoosta [38]
Yes, ratio can be expressed in percentage.
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