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Margarita [4]
3 years ago
11

Mason notices that his boat sinks lower into the water in a freshwater lake than in the ocean. What could explain this?

Physics
2 answers:
suter [353]3 years ago
5 0

<u>Answer </u>

D. Salt water is denser than freshwater.

<u>Explanation</u>

A boat is able to float on water because it experiences an upthrust upwards.

The magnitude of the upthrust depends on the density of the liquid.

When the liquid is denser the boat will experience a great upthrust as compared to when in a less dense liquid.

If the boat sinks lower in the freshwater than in salty water, then Salt water is more dense than freshwater.



Ludmilka [50]3 years ago
5 0

Answer: D) Salt water is more dense than freshwater.

Explanation: Suppose that you have a glass of water, and you put a little amount of salt in it and mix it.

Now you may see that there is more matter in the glass (the volume of the solution inside the glass also may increase, but not in an appreciable magnitude compared with the increase in mass). And you may know, the density is calculated:

Density = Mass/volume

So if you have more mass in the same volume, this means that the density increases.

And is easier to float in a denser medium than in a low density medium (is easier to float in honey than in water, for example)

So if the medium if denser, the boat will float more easily.

Then the right answer is option D:  Salt water is more dense than freshwater

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An ideal spring is mounted horizontally, with its left end fixed. The force constant of the spring is 170 N/m. A glider of mass
gizmo_the_mogwai [7]

Answer:

Explanation:

First of all we shall find the velocity at equilibrium point of mass 1.2 kg .

It will be ω A , where ω is angular frequency and A is amplitude .

ω = √ ( k / m )

= √ (170 / 1.2 )

= 11.90 rad /s

amplitude A = .045 m

velocity at middle point ( maximum velocity ) = 11.9 x .045 m /s

= .5355 m /s

At middle point , no force acts so we can apply law of conservation of momentum

m₁ v₁ = ( m₁ + m₂ ) v

1.2 x .5355 = ( 1.2 + .48 ) x v

v = .3825 m /s

= 38.25 cm /s

Let new amplitude be A₁ .

1/2 m v² = 1/2 k A₁²

( 1.2 + .48 ) x v² = 170 x A₁²

( 1.2 + .48 ) x .3825² = 170 x A₁²

A₁ = .0379 m

New amplitude is .0379 m

7 0
3 years ago
Illustrate a body of mass 5.0kg pulled by horizontal force F . if the body accelerates 2.0ms² and experience a frictional force
Natasha2012 [34]

Explanation:

a. Net force is mass times acceleration (Newton's second law).

∑F = ma

∑F = (5.0 kg) (2.0 m/s²)

∑F = 10 N

b. The net force is the sum of the individual forces.

10 N = F − 5 N

F = 15 N

c. Friction force here is mgμ.

mgμ = 5 N

(5.0 kg) (10 m/s) μ = 5 N

μ = 0.1

3 0
3 years ago
If a reaction starts with 30 grams how many should it end with ?
zysi [14]

30grams

Explanation:

If a reaction starts with 30grams then the reaction should end with 30grams.

This in conformity with the law of conservation of mass.

  • The law states that "in an isolated system, mass is neither created nor destroyed during chemical transformation".
  • Mass is the quantity of matter contained in a substance.
  • In chemical reactions, the mass of reactants must always be the same with the mass of the product baring any loss.
  • In an isolated system, there is no exchange of energy and mass.
  • Chemical systems are usually treated as isolated systems in which mass is conserved.

Learn more:

Chemical laws brainly.com/question/5896850

#learnwithBrainly

4 0
3 years ago
19) A child on a sled starts from rest at the top of a 15.0° slope. If the trip to the bottom takes 15.2 s,
sveticcg [70]

Answer: 288.8 m

Explanation:

We have the following data:

t=15.2 s is the time it takes to the child to reach the bottom of the slope

V_{o}=0 is the initial velocity (the child started from rest)

\theta=15\° is the angle of the slope

d is the length of the slope

Now, the Force exerted on the sled along the ramp is:

F=ma (1)

Where m is the mass of the sled and a its acceleration

In addition, if we draw a free body diagram of this sled, the force along the ramp will be:

F=mg sin \theta (2)

Where g=9.8 m/s^{2} is the acceleration due gravity

Then:

ma=mg sin \theta (3)

Finding a:

a=g sin \theta (4)

a=9.8 m/s^{2} sin(15\°) (5)

a=2.5 m/s^{2} (6)

Now, we will use the following kinematic equations to find d:

V=V_{o}+at (7)

V^{2}=V_{o}^{2}+2ad (8)

Where V is the final velocity

Finding V from (7):

V=at=(2.5 m/s^{2})(15.2 s) (9)

V=38 m/s (10)

Substituting (10) in (8):

(38 m/s)^{2}=2(2.5 m/s^{2})d (11)

Finding d:

d=288.8 m

6 0
3 years ago
A book starts on a shelf 1 m off of the ground. You then move the book to a higher shelf that is 3 m off of the ground. If the s
JulsSmile [24]

Answer:

Using g = 9.8: 1.02 kg, Using g = 10: 1 kg

Explanation:

E = mgh

20 = m(9.8)(3 - 1)

20 = 9.8m(2)

20 = 19.6m

m = 1.02 kg

I'm now assuming you may be using a g constant of 10, thus the close integer result, in which case the mass would be exactly 1 kilogram.

4 0
3 years ago
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