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evablogger [386]
3 years ago
5

Solve this question now ​

Mathematics
1 answer:
sattari [20]3 years ago
3 0

Answer:

Center is (1,5) ;Radius is the square root of 13

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The legs of an isosceles right triangle are 5 inches long. What is the length of the hypotenuse of the triangle to the nearest i
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The legs are 5 inches long.

Use the Pythagorean theorem:
5^2+5^2=c^2 \\
25+25=c^2 \\
50=c^2 \\
c=\sqrt{50} \\
c=\sqrt{25 \times 2} \\
c=5 \sqrt{2} \\
c \approx 7

The length of the hypotenuse of the triangle is approximately 7 inches long.
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Ok y is your y value from any point on the graph m is your slope x is the x value of any point from the graph and b is your y intercept that is where the line cross in the y line that is the vertical line in the graph

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The answer would be 1
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2 years ago
Find the area of the shaded region. Round your answer to the nearest tenth.
Alex
Check the picture below on the left-side.

we know the central angle of the "empty" area is 120°, however the legs coming from the center of the circle, namely the radius, are always 6, therefore the legs stemming from the 120° angle, are both 6, making that triangle an isosceles.

now, using the "inscribed angle" theorem, check the picture on the right-side, we know that the inscribed angle there, in red, is 30°, that means the intercepted arc is twice as much, thus 60°, and since arcs get their angle measurement from the central angle they're in, the central angle making up that arc is also 60°, as in the picture.

so, the shaded area is really just the area of that circle's "sector" with 60°, PLUS the area of the circle's "segment" with 120°.

\bf \textit{area of a sector of a circle}\\\\
A_x=\cfrac{\theta \pi r^2}{360}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=6\\
\theta =60
\end{cases}\implies A_x=\cfrac{60\cdot \pi \cdot 6^2}{360}\implies \boxed{A_x=6\pi} \\\\
-------------------------------\\\\

\bf \textit{area of a segment of a circle}\\\\
A_y=\cfrac{r^2}{2}\left[\cfrac{\pi \theta }{180}~-~sin(\theta )  \right]
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=6\\
\theta =120
\end{cases}

\bf A_y=\cfrac{6^2}{2}\left[\cfrac{\pi\cdot 120 }{180}~-~sin(120^o )  \right]
\\\\\\
A_y=18\left[\cfrac{2\pi }{3}~-~\cfrac{\sqrt{3}}{2} \right]\implies \boxed{A_y=12\pi -9\sqrt{3}}\\\\
-------------------------------\\\\
\textit{shaded area}\qquad \stackrel{A_x}{6\pi }~~+~~\stackrel{A_y}{12\pi -9\sqrt{3}}\implies 18\pi -9\sqrt{3}

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3 years ago
Order the number 7/4, 1.6, 1 5/8, 1.65 from least to greatest.
Debora [2.8K]
Here are the numbers from least to greatest     
1.6,1.65,15/8,7/4
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