All categories

3 years ago

What do electric and magnetic fields contain and transport?

Physics

1 answer:

SSSSS [86.1K]3 years ago

8 0

They are imaginary lines of forces. They don't contain anything other than energy.

You might be interested in

The force diagram shown here describes the forces that external objects (the surface andEarth) exert on a woman (in this scenari

sveticcg [70]

The three different motions are;

The upward motion of the woman is constant
The downward motion of the woman is also constant
The horizontal motion of the woman is zero.

<h3>What is force diagram?</h3>

Force diagram is a pictorial or graphical illustration of different forces acting on object.

In this given question, there two forces acting on the woman as depicted in the force diagram.

The first force is surface force (Fs)
The second force is force of Earth (FE)

In the given force diagram, the woman is in equilibrium, this implies that the surface force and the Earth force are equal.

The three different types of motion of the woman that are consistent with the force diagram include the following;

The upward motion of the woman is constant
The downward motion of the woman is also constant
The horizontal motion of the woman is zero since there is no horizontal force on the woman.

Learn more about force diagram here: brainly.com/question/3624253

#SPJ1

4 0

10 months ago

_____ help by supporting the plant and holding the leaves up to the light.

Semenov [28]

The answer is the stem.

7 0

3 years ago

Read 2 more answers

What is a concern about recovered memories?

Fittoniya [83]

Answer:

D because those are both concerning.

4 0

3 years ago

Read 2 more answers

Which of the following is not a reason fluorescent lamps are advantages over incandescent lamps?

iren2701 [21]

It’s because flourecent lights operate at higher temperatures than incadecent lights.

3 0

3 years ago

An electron moving parallel to a uniform electric field increases its speed from 2.0 × 107 m/s to 4.0 × 107 m/s over a distance

jeka94

Answer:

$1.8\times 105 N/C$

Explanation:

We are given that

$u=2\times 10^7 m/s$

$v=4\times 10^7 m/s$

d=1.9 cm= $\frac{1.9}{100}=0.019 m$

Using 1m=100 cm

We have to find the electric field strength.

$v^2-u^2=2as$

Using the formula

$(4\times 10^7)^2-(2\times 10^7)^2=2a(0.019)$

$16\times 10^{14}-4\times 10^{14}=0.038a$

$0.038a=12\times 10^{14}$

$a=\frac{12}{0.038}\times 10^{14}=3.16\times 10^{16}m/s^2$

$q=1.6\times 10^{-19} C$

Mass of electron,m $=9.1\times 10^{-31} kg$

$E=\frac{ma}{q}$

Substitute the values

$E=\frac{9.1\times 10^{-31}\times 3.16\times 10^{16}}{1.6\times 10^{-19}}$

$E=1.8\times 105 N/C$

7 0

3 years ago