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vekshin1
3 years ago
5

Whereas asteroids are compromised primarily of (Blank), comets are compromised primarily of.

Chemistry
1 answer:
Bingel [31]3 years ago
6 0
I think it is A rocky material; icy material
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When a tip of a plant is cut it doesn't grow well​
aleksandr82 [10.1K]

Explanation:

the tip of a growing plant contains special rapidly diving cells called apical meristem ,these cells are responsible for increase in the length of the plant . if we cut out these cells ,length growth of the plant will be stunned as these cells are not present anyplace else.

8 0
3 years ago
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A magnet was placed near a pile that contained both iron and sulfur. The magnet was moved gradually closer to the pile. As it ne
irina1246 [14]

The question is incomplete, the complete question is;

A magnet was placed near a pile that contained both iron and sulfur. The magnet was moved gradually closer to the pile. As it neared the pile, the magnet started attracting small pieces of iron from the pile. Which of these statements best describes the contents of the pile?

F. It is a homogeneous mixture of iron and sulfur.   G. It is a heterogeneous mixture of iron and sulfur.   H. It is a compound that contains both iron and sulfur.   I. It is a compound that can be separated by magnetism.

Answer:

G. It is a heterogeneous mixture of iron and sulfur.

Explanation:

A heterogeneous  mixture is one that does not have a uniform composition throughout.

We must recall that a mixture is any combination of substances that do not chemically react together and are separable by physical means.

Having said this, it is clear that I can separate the iron from sulphur by simple magnetic (physical) means. Hence,  it is a heterogeneous mixture of iron and sulfur.

4 0
3 years ago
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Deposition is a _____ force since it involves dumping sediment in a particular location.
Oduvanchick [21]

Answer:

D) constructive

Explanation:

Deposition is a constructive force since it involves dumping sediment in a particular location.

3 0
4 years ago
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Rank the compounds by the ease with which they ionize under sn1 conditions. rank the compounds from easiest to hardest. to rank
marysya [2.9K]
The rate of Formation of Carbocation mainly depends on two factors'

                    1)  Stability of Carbocation:
                                                              The ease of formation of Carbocation mainly depends upon the ionization of substrate. If the forming carbocation id tertiary then it is more stable and hence readily formed as compared to secondary and primary.

                     2) Ease of detaching of Leaving Group:
                                                                                   The more readily and easily the leaving group leaves the more readily the carbocation is formed and vice versa. In given scenario the carbocation formed is tertiary in all three cases, the difference comes in the leaving group. So, among these three substrates the one containing Iodo group will easily dissociate to form tertiary carbocation because due to its large size Iodine easily leaves the substrate, secondly Chlorine is a good leaving group compared to Fluoride. Hence the order of rate of formation of carbocation is,

                                            R-I > R-Cl > R-F

                                               B   >  C  >  A

3 0
3 years ago
Determine the molecular formula for the compound with a molar mass of 46.08 g/mol and the following percent compostion:
kramer

Answer:

      \large\boxed{\large\boxed{CH_6N_2}}

Explanation:

<u><em>1. First determine the empirical formula.</em></u>

a) Base: 100 g of compound

             mass       atomic mass      number of moles

                g                g/mol                    mol

C           26.06            12.011             26.06/12.011   = 2.17

H           13.13              1.008              13.13/1.008    =  13.03

N           60.81             14.007            60.81/14.007 = 4.34

b) Divide every number of moles by the smallest number: 2.17

mass       number of moles        proportion

C                  2.17/2.17                         1

H               13.03/2.17                         6

N                4.34/2.17                          2

c) Empirical formula

      CH_6N_2

d) Mass of the empirical formula

      1\times 12.011g/mol6+6\times 1.008g/mol+2\times 14.007g/mol=46.07g/mol

<u><em>2. Molecular formula</em></u>

Since the mass of one unit of the empirical formula is equal to the molar mass of the compound, the molecular formula is the same as the empirical formula:

                   CH_6N_2

6 0
3 years ago
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