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qwelly [4]
2 years ago
13

7. Calculate the amount of sodium hydroxide you will need to make 250 mL of a 0.1 M solution of sodium hydroxide.

Chemistry
1 answer:
tresset_1 [31]2 years ago
7 0

Answer:

1 g

Explanation:

Given data:

Volume of solution = 250 mL (250 mL × 1 L/1000 mL = 0.25 L)

Molarity of solution = 0.1 M

Amount of sodium hydroxide = ?

Solution:

Molarity = number of moles / volume in L

0.1 M = number of moles /0.25 L

Number of moles = 0.1 M × 0.25 L

            M = mol/ L

Number of moles = 0.025 mol

Mass of sodium hydroxide:

Mass = number of moles × molar mass

Mass = 0.025 mol ×40 g/mol

Mass = 1 g

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3- Fully folded proteins typically have polar side chains on their surfaces, where electrostatic attractions and hydrogen bonds
Elden [556K]

Answer:

Option C= A hydrogen bond formed between a polar side chain and a hydrophobic side chain.

Explanation:

All three given options a, b and d have common mechanism to accommodate the polar amino acid.

A= A hydrogen bond forms between two polar side chains.

B= A hydrogen bond from between a polar side chain and protein back bone.

D =  hydrogen bond form between polar side chains and a buried water molecules.

All these are use to accommodate the polar amino acid.

While option C is not used. which is:

A hydrogen bond formed between a polar side chain and a hydrophobic side chain.

5 0
3 years ago
Which particle has a mass of approximately 1 atomic mass unit?
labwork [276]
The answer is D) a neutron.

When we say an atom's mass is, like 5 atomic mass units actually we are saying that the total number of the neutrons and protons in its nucleus is 5.

The mass of a neutron and a proton is each one atomic mass unit.

Mass of a neutron is approximately 1 atomic mass unit.
7 0
3 years ago
2. Calculate the density of a metal that occupies 17.75 cm and has a mass of 342.93 g. [D = m/V]
satela [25.4K]

Answer:

19.32

Explanation:

the density is given by the mass over volume

the mass In this case is 342.93 and the volume is 17.75

d=342.93g/17.75cm

=19.32g/cm

i hope this helps

3 0
2 years ago
How long does it take to electroplate 0.5 mm of gold on an object with a surface area of 31 cm^^ from an Au3+(aq) solution with
konstantin123 [22]

Answer:

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

Explanation:

Mass of gold = m

Volume of gold = v

Surface area on which gold is plated = a=31 cm^2

Thickness of the gold plating  = h = 0.5 mm = 0.05 cm

1 mm = 0.1 cm

V=a\times h=31 cm^2\times 0.05 cm=1.55 cm^3

Density of the gold = d=19.3 g/cm^3

m=d\times v=19.3 g/cm^3\times 1.55 cm^3=29.915g

Moles of gold = \frac{29.915 g}{197 g/mol}=0.152 mol

Au^{3+}+3e^-\rightarrow Au

According to reaction, 1 mole of gold required 3 moles of electrons,then 0.152 moles of gold will require :

\frac{3}{1}\times 0.152 mol=0.456 mol of electrons

Number of electrons = N =0.456\times \times 6.022\times 10^{23}

Charge on single electron = q=1.6\times 10^{-19} C

Total charge required = Q

Q=N\times q

Amount of current passes = I = 8 Ampere

Duration of time  = T

I=\frac{Q}{T}

T=\frac{N\times q}{I}

=\frac{0.456\times \times 6.022\times 10^{23}\times 1.6\times 10^{-19} C}{8 A}=5492 s

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

7 0
3 years ago
Which of these is an example of a physical change?
trasher [3.6K]
Ain't is the correct answer
8 0
3 years ago
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