Answer:
255.51cm3
Explanation:
Data obtained from the question include:
V1 (initial volume) =?
T1 (initial temperature) = 50°C = 50 + 273 = 323K
T2 (final temperature) = - 5°C = - 5 + 237 = 268K
V2 (final volume) = 212cm3
Using the Charles' law equation V1/T1 = V2/T2, the initial volume of the gas can be obtained as follow:
V1/T1 = V2/T2
V1/323 = 212/268
Cross multiply to express in linear form
V1 x 268 = 323 x 212
Divide both side by 268
V1 = (323 x 212)/268
V1 = 255.51cm3
Therefore, the initial volume of the gas is 255.51cm3
use a mortar & pestle to grind the solute into smaller particles, thus increasing the surface area.
Answer:
C is the answer hope I helped you have a good day by
varying composition is not a property of a pure substance
Answer:

Explanation:
We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.

The mass is 5 grams, the specific heat capacity is 0.14 Joules per gram degree Celsius. Let's find the change in temperature.
- ΔT= final temperature - initial temperature
- ΔT= 95°C - 15°C = 80°C
We know the variables and can substitute them into the formula.


Multiply the first numbers. The grams will cancel.

Multiply again. This time the degrees Celsius cancel.

56 Joules of heat are needed.