2. A solution in which 50 grams of salute is dissolved in 250 grams of solution has a concentration of
1 answer:
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Answer:
The total number of moles of gas in the mixture is 0.16939.
1.25550 grams of methane gas and 3.18848 grams of oxygen gas.
Explanation:
Total volume of the mixture = V = 10.5 L
Temperature of the mixture = T = 35°C = 308.15K
Pressure of the mixture = P
Total moles of mixture = n =
Using an ideal gas equation :
Partial pressure of the methane=
Moles of the methane=
Partial pressure of the oxygen gas=
Moles of the methane=
Mole fraction of the methane=
Mole fraction of the oxygen gas=
(Dalton's law)
Mass of 0.06975 moles of methane gas :
0.06975 mol × 18 g/mol =1.25550 g
(Dalton's law)
Mass of 0.06975 moles of oxygen gas :
0.09964 mol × 32 g/mol =3.18848 g
Total moles of mixture = n =
[/tex]=0.06975 mol+0.09964 mol=0.16939 mol[/tex]