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FinnZ [79.3K]
3 years ago
5

2. A solution in which 50 grams of salute is dissolved in 250 grams of solution has a concentration of

Chemistry
1 answer:
IgorC [24]3 years ago
5 0
The fact that the unit is supposed to be in percent makes me think it is referring to percent mass.  To find percent mass you need to find find the divide the mass of solute by the total mass of solution and than multiply that by 100%.
%mass=(50g/300g)x100%
%mass=0.167%

I hope this helps.
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svetlana [45]

Answer:

255.51cm3

Explanation:

Data obtained from the question include:

V1 (initial volume) =?

T1 (initial temperature) = 50°C = 50 + 273 = 323K

T2 (final temperature) = - 5°C = - 5 + 237 = 268K

V2 (final volume) = 212cm3

Using the Charles' law equation V1/T1 = V2/T2, the initial volume of the gas can be obtained as follow:

V1/T1 = V2/T2

V1/323 = 212/268

Cross multiply to express in linear form

V1 x 268 = 323 x 212

Divide both side by 268

V1 = (323 x 212)/268

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Select the correct answer.
Ilya [14]

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Calculate: A. Mercury has a specific Heat Capacity of 0.14 J/goC. How much heat is needed to raise the thermometer temperature 1
kari74 [83]

Answer:

\boxed {\boxed {\sf 56 \ Joules}}

Explanation:

We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.

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We know the variables and can substitute them into the formula.

m= 5 \ g \\c= 0.14 \ J/ g \ \textdegree C \\\Delta T= 80 \ \textdegree C

q= (5 \ g )( 0.14 \ J/ g \ \textdegree C ) ( 80 \ \textdegree C)

Multiply the first numbers. The grams will cancel.

q= 0.7 \ J/ \textdegree C(80 \ \textdegree C )

Multiply again. This time the degrees Celsius cancel.

q= 56 \ J

56 Joules of heat are needed.

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