[
] value of soft drink is 0.0001mol/l when given pH is 4.
Given:
pH = 4
Needs to find: [
]
Formula to find: pH=−log
[
]
We can put the values of pH in above formula as,
pH=−log
[
]
4 =−log
[
]
To calculate hydonium ion concentration, formula is as follows;
[
] = 
[
] =
= 0.0001mol/l
[
] value of soft drink is 0.0001mol/l
Learn more about pH here:
brainly.com/question/2288405
#SPJ4
Answer:
C
Explanation:
Angiosperms have developed these adaptations because it attracts pollinators which helps the ecosystem grow.
Answer:
The reactions free energy 
Explanation:
From the question we are told that
The pressure of (NO) is 
The pressure of (Cl) gas is 
The pressure of nitrosly chloride (NOCl) is 
The reaction is
⇆ 
From the reaction we can mathematically evaluate the
(Standard state free energy ) as

The Standard state free energy for NO is constant with a value

The Standard state free energy for
is constant with a value

The Standard state free energy for
is constant with a value

Now substituting this into the equation

The pressure constant is evaluated as

Substituting values


The free energy for this reaction is evaluated as

Where R is gas constant with a value of 
T is temperature in K with a given value of 
Substituting value
![\Delta G = -43 *10^{3} + 8.314 *298 * ln [0.0765]](https://tex.z-dn.net/?f=%5CDelta%20%20G%20%20%3D%20-43%20%2A10%5E%7B3%7D%20%2B%208.314%20%2A298%20%2A%20ln%20%5B0.0765%5D)


Answer: The final temperature in Kelvin is 1488
Explanation:
To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,

where,
are the initial pressure and temperature of the gas.
are the final pressure and temperature of the gas.
We are given:

Putting values in above equation, we get:

Hence, the final temperature in Kelvin is 1488
1.1 moles of C10H8 is the limiting reagent in the reaction between reaction C10H8 and O2
.
C10H8 + 12O2 ----> 10CO2 + 4H2O
C10H8 is the limiting reagent since 1.1 moles of C10H8 is totally consumed during the reaction