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Free_Kalibri [48]
3 years ago
12

Select the correct answer.

Chemistry
1 answer:
Ilya [14]3 years ago
3 0

Answer:

C is the answer hope I helped you have a good day by

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What is the temperature of 0.47 mol of gas at a pressure of 1.5 atm and a volume of 10.5 l ?
Whitepunk [10]
The temp is 0.002448 of the equation
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A salt solution with a volume of 250 mL that contains 0.70 mol NaCl.
uysha [10]
 <span>0.70 mol/0.250 L = 2.8 M</span>
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Order these clouds from highest (1) to lowest (3):
tatiyna
Stratus clouds reside below the 6,000ft range.
Altocumulus clouds reside in the 6,500-20,000ft range.
Cirrus clouds reside above the 20,000ft range.

Ordered from highest to lowest, the sequence of clouds will be:
Cirrus
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5 0
3 years ago
An aqueous solution contains the following ions: cl−, ag , pb2 , no−3, and so2−4. More than one precipitate will form. Identify
klasskru [66]

An aqueous solution contains the following ions Cl⁻, Ag⁺, Pb²⁺, NO₃⁻ & SO₄²⁻ and more than one precipitate will form are AgCl, PbCl₂, PbSO₄ & Ag₂SO₄.

<h3>What is precipitate?</h3>

Precipitate is the insoluble compound which is present at the bottom of any chemical reaction in the solid state.

If in an aqueous solution Cl⁻, Ag⁺, Pb²⁺, NO₃⁻ & SO₄²⁻ ions are present then:

  • Compounds AgCl, PbCl₂, PbSO₄ & Ag₂SO₄ are not soluble in water as it is present in the form of precipitate.
  • Pb(NO₃)₂ is fully soluble in water and will not make precipitate.

Hence precipitates are AgCl, PbCl₂, PbSO₄ & Ag₂SO₄.

To know more about precipitates, visit the below link:

brainly.com/question/2437408

#SPJ4

8 0
2 years ago
A container of carbon dioxide has a volume of 240 mL at a temperature of 22°C. If the pressure remains constant, what is the vol
astraxan [27]

Answer:

Volume of the CO_{2} gas at 44°C is <u>258 ml.</u>

Explanation

here,

using Charles' law ,

\frac{V}{T} =\frac{v}{t}

where , V= initial volume          v= final volume

             T=initial temperature    t = final temperature

Given - pressure is constant ,

so , putting the values -

V= 240ml

T= 22 + 273K = 295K                      (since converting celsius into kelvin that

                                                         is +273K )

v =?

t = 44+ 273K = 317K

Now , putting the given values in charles' law ,

\frac{240ml}{295K} =\frac{v}{317K}

240ml x317K = v x 295K     (through cross multiplication )

v =\frac{240ml\times317K}{295K}

= 258ml .

thus ,<u> the volume of carbon dioxide in a container at 44°C IS 258ml .</u>

7 0
3 years ago
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