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Snezhnost [94]
3 years ago
10

A thermometer that was used in a calorimeter was consistently 2.7 °c too high. how would this affect the calculations of δh for

the reactions conducted in the calorimeter?
Chemistry
1 answer:
vodomira [7]3 years ago
7 0
The calorimetry experiment is usually done to determine the heat capacity of the sample. The working equation would be:

Q = mCpΔT
Q is the energy
m is the mass of sample
Cp is the heat capacity
ΔT is the temperature

So, if the thermometer is too high, then that would affect ΔT, which would make it greater. Consequently, you would calculate a much lesser heat capacity of the sample compared to the theoretical value.
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Which type of substance is an electron-pair acceptor?
Ghella [55]

Answer:

Explanation:

A lewis acid is an electron pair acceptor. A definition of a lewis acid is something that when dissolves in water produces hydrogen ions (protons). Hence, this positively charged particle can then accept non bonding electrons and can hence be called an electron pair acceptor.

5 0
3 years ago
7
Umnica [9.8K]
Answer: Volume im pretty sure
3 0
2 years ago
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Imagine you need to explain to a friend how to convert a value on a food label to one that is measured in grams. Assume the pack
Mariulka [41]

Answer:

453.592 grams

Explanation:

Given

Mass = 1 lb

Required.

Convert to grams using dimensional analysis

Represent 1 lb with x g

In unit conversion, we have that.

1 lb = 453.592 g

So:

Getting the equivalent of lb in g, we have:

x g = 1 lb * (453.592 g/ 1 lb)

x g = 1 * 453.592 g

x g = 453.592 grams

Hence:

The equivalent of 1 lb in grams is 453.592 grams

4 0
3 years ago
Rosa preparo una disolución de agua salada mezclando 120 mg de agua con 5 mg de sal comun ¿ que concentración tiene la disolució
enot [183]

Concentration of the solution (% mass) = 4%

<h3>Further explanation</h3>

<em>Rosa prepared a salt water solution by mixing 120 mg of water with 5 mg of common salt, what concentration is the solution she prepare?</em>

<em />

<em />\tt \%mass=\dfrac{mass~solute}{mass~solution}\times 100\%<em />

mass solute=mass of salt=5 mg

mass solution :

mass solute(salt)+mass solvent(water) :

\tt 5~mg+120~mg=125~mg

\tt \%mass=\dfrac{5~mg}{125~mg}\times 100\%\\\\\%mass=4

3 0
3 years ago
What is the difference between a volume that is delivered and a volume that is contained?
nikdorinn [45]

Answer:

When the graduation line denotes the volume contained in the calibrated vessel, the ware is marked “TC”. When the graduation line indicates the volume delivered from the vessel, the ware is marked “TD”.

3 0
3 years ago
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