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tino4ka555 [31]
3 years ago
6

Rosa preparo una disolución de agua salada mezclando 120 mg de agua con 5 mg de sal comun ¿ que concentración tiene la disolució

n que preparo ?
Chemistry
1 answer:
enot [183]3 years ago
3 0

Concentration of the solution (% mass) = 4%

<h3>Further explanation</h3>

<em>Rosa prepared a salt water solution by mixing 120 mg of water with 5 mg of common salt, what concentration is the solution she prepare?</em>

<em />

<em />\tt \%mass=\dfrac{mass~solute}{mass~solution}\times 100\%<em />

mass solute=mass of salt=5 mg

mass solution :

mass solute(salt)+mass solvent(water) :

\tt 5~mg+120~mg=125~mg

\tt \%mass=\dfrac{5~mg}{125~mg}\times 100\%\\\\\%mass=4

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Answer:

atomic mass. You will have created an isotope.

Explanation:

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Select the correct answer. Which of these elements is a transition metal?
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I don't see the options for an answer, so here is a list of all of the transition metals lol

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2 years ago
Which two substances are covalent compounds? * C6H12O6(s) and KI(s) C6H12O6(s) and HCl(g) KI(s) and NaCl(s) NaCl(s) and HCl(g)
Ray Of Light [21]

Answer: Option (b) is the correct answer.

Explanation:

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For example, C_{6}H_{12}O_{6} and HCl is also a covalent compound.

And, a compound in which transfer of electrons occur between the combining atoms is known as an ionic compound. Whenever, a metal chemically combines with a non-metal then it will always lead to the formation of an ionic compound.

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3 years ago
58. A cylinder of a gas mixture used for calibration of blood gas analyzers in medical laboratories contains 5.0% CO2, 12.0% O2,
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<em><u>Answer and Explanation:</u></em>

Greetings!

Let's~answer~your~question!

Partial ~pressure ~of ~gas ~can ~be ~directly~ calculated ~by ~multiplying ~the~ percentage\\ of~ pressure~ of~ gases~ to ~the ~total ~pressure.

\boxed{Pgas~ = ~P~total~ * \% ~P ~of ~gas}

<em><u>For % of N2 gas: </u></em>

<em><u /></em>100\% - (5\% + 12\%) = 83\% ~N2<em><u /></em>

<em><u /></em>

<em><u /></em>PN_2 ~= ~146~ atm~ *~ 0.83 ~ = 121.18 ~atm<em><u /></em>

<em><u /></em>PO_2 ~= ~146~ atm~ *~ 0.12~ = 17.52 ~atm<em><u /></em>

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