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Naily [24]
3 years ago
11

The vapor pressure of pure water at 25 °C is 23.8 torr. Determine the vapor pressure (torr) of water at 25 °C above a solution p

repared by dissolving 35 g of urea (a nonvolatile, non-electrolyte, molar mass = 60.0 g/mol) in 75 g of water.
Chemistry
1 answer:
siniylev [52]3 years ago
7 0

Answer:

Vapor pressure of solution = 20.8 Torr

Explanation:

This is about vapor pressure lowering

ΔP  = P° . Xm

ΔP states the difference between vapor pressure of pure solvent and vapor pressure from solution.

P° is the vapor pressure of pure solvent.

Xm means mole fraction (mol of solute / mol of solute + mol of solvent)

Let's determine the mol of solute

35 g / 60 g/mol = 0.583 mol of urea

Let's determine the mol of solvent

75 g / 18 g/mol = 4.167 mol of water

Total moles = 0.583 + 4.167 = 4.75

Mole fraction of solute → 0.583 /4.75 = 0.123

Let's replace the data in the formula:

23.8Torr - Vapor pressure of solution = 23.8 Torr . 0.123

Vapor pressure of solution = - (23.8 Torr . 0.123 - 23.8 Torr)

Vapor pressure of solution = 20.8 Torr

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3420‬m

Explanation:

Given parameters:

Length of path = 6200m

time taken for the horse to run = 22.5min

speed = 152meters/minute

Unknown:

Distance run by the horse = ?

Solution:

Speed is the rate of change of distance with time.

   Speed       =    \frac{distance}{time}

    Distance = speed x time

 

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Fofino [41]

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Explanation:

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The mass of atoms of carbon and 3 molecules of hydrogen​ : 18 g/mol

<h3>Further explanation </h3>

An atomic mass unit ( amu or "u") is a relative atomic mass of 1/12 the mass of an atom of carbon-12.  

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The mass of atom of Carbon(C)⇒Ar = 12 g/mol

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The mass of 3 molecules of Hydrogen : 3 x 2 = 6 g/mol

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when 6.0 mol of oxygen are confined in a 36L vessel at 196°c, the pressure is 8atm. what is the new pressure for oxygen expands
kykrilka [37]

<u>Answer:</u> The new pressure for oxygen gas is 6 atm.

<u>Explanation:</u>

To calculate the new pressure of the gas, we use the equation given by Boyle's Law.

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Mathematically,

P\propto \frac{1}{V}

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where,

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P_2\text{ and }V_2 are the final pressure and volume of the gas.

We are given:

P_1=8atm\\V_1=36L\\P_2=?atm\\V_2=48L

Putting values in above equation, we get:

8atm\times 36L=P_2\times 48L\\\\P_2=6atm

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