Answer:
Explanation:
If a baseball is hit into the air with a velocity of 27 m/s, we want to determine the maximum height of the ball. Using the projecile formula;
Max height H = u²/2g
u is the initial velocity of the body = 27m/s
g is the acceleration due to gravity = 9.81m/s²
H = 27²/2(9.81)
H = 729/19.62
H = 37.16m
Hence the ball went 37.16m high
Electrical energy.................
Answer:
a) V1=11.05m/s V2=92.07m/s V3=17.24m/s
b) KE = 16238.26J
Explanation:
For tangential speeds:
For the kinetic energy, it can be calculated as:
Where:
So,
KE=16238.26J
Answer:For this equation you would have to take the numerator and multiply with the other one, which would leave you with 24/80 and if you want the simplified version it would be 3/10, hope this helps! :)
Explanation:
