Answer:
If
0.0357
mol
CaCl
2
is dissolved in water to make a
0.420
M
solution, what is the volume of the solution?
Alright, so that means we have 0.68 mol of the compound
For each 1 mol of the compound, we have 4*1 oxygens (because there are four oxygens in the formula)
Therefore for each 0.68 mol of the compound, we have 4*0.68 moles of oxygen!
Protons have the same mass as B. Neutrons. They have almost the same exact mass.
57.1g * 6.022*10^23 / 22.9 * 2 = 7.51*10^23 molecules
The temperature of the gas sample is 813 K.
<u>Explanation:</u>
We have to use the ideal gas equation to find the temperature of the gas sample.
The ideal gas equation is PV = nRT
Pressure, P = 429 mm Hg = 0.56 atm
Volume, V = 560 mL = 0.56 L
R = gas constant = 0.08205 L atm mol⁻¹K⁻¹
Mass = 0.211 g
Molar mass of carbon di oxide = 44.01 g / mol
Moles, n = 
= 0.0047 mol
Now, we have to plugin the above values in the above equation, we will get the temperature as,

T = 
= 813 K
So the temperature of the gas sample is 813 K.