Question

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Answer 1

Answer:

d. 12.3 grams of Al2O3

Explanation:

Based on the reaction:

4Al + 3O2 → 2Al2O3

Where 4 moles of Al reacts in excess of oxygen to produce 2 moles of aluminium oxide.

To solve this question we must find the moles of Aluminium. With these moles we can find the moles of aluminium oxide using the reaction:

Moles Al -Molar mass: 26.9815g/mol-

6.50g * (1mol / 26.9815g) = 0.241 moles Al

Mass Al₂O₃ -Molar mass: 101.96g/mol-

0.241 moles Al * (2 mol Al2O3 / 4 mol Al) = 0.120 moles Al2O3

0.120 moles Al2O3 * (101.96g / mol) =

12.3g of Al2O3 are produced.

Right answer is:

d. 12.3 grams of Al2O3