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3 years ago

PLeaseee ITS Timedddd + BrainlIESTT

Chemistry

1 answer:

zmey [24]3 years ago

8 0

Answer:

d. 12.3 grams of Al2O3

Explanation:

Based on the reaction:

4Al + 3O2 → 2Al2O3

<em>Where 4 moles of Al reacts in excess of oxygen to produce 2 moles of aluminium oxide.</em>

<em />

To solve this question we must find the moles of Aluminium. With these moles we can find the moles of aluminium oxide using the reaction:

<em>Moles Al -Molar mass: 26.9815g/mol-</em>

6.50g * (1mol / 26.9815g) = 0.241 moles Al

<em>Mass Al₂O₃ -Molar mass: 101.96g/mol-</em>

0.241 moles Al * (2 mol Al2O3 / 4 mol Al) = 0.120 moles Al2O3

0.120 moles Al2O3 * (101.96g / mol) =

12.3g of Al2O3 are produced.

Right answer is:

<h3>d. 12.3 grams of Al2O3 </h3>

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Answer:

A. Because they are compounds, they cannot be pure substances.

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The false statement from the given choices is that because they are compounds they cannot be pure substances. In fact, because they are compounds they are pure substances.

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All parts are the same throughout
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3 years ago

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3 years ago

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lesya692 [45]

Answer: The given transition metal ions in order of decreasing number of unpaired electrons are as follows.

$Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}$

Explanation:

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So, there are only 2 unpaired electrons present in $V^{3+}$ .

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$Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}$

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$Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}$

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This should be the right structural formula:

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