Answer:
Consecutive odd integers are 19 , 21 & 23
Step-by-step explanation:
Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).
According to the question,
Eliminating 2x from both the sides,
So, the consecutive odd integers are = 19 , 21 & 23.
Answer: 22
Step-by-step explanation: Perimeter of a rectangle is 2H + 2B = P
if each side has 28 feet then 28* 2 = 56. We take 100 - 56 = 44. Then we take 44/2 to find one remaining side = 22.
Volume is legnth times widht times height
lenght=2x-1
width=x-2
height=x+1
multiply all together
use mass distributive property
distributive=a(b+c)=ab+ac so extending that
(a+c)(c+c)=(a+b)(c)+(a+b)(d) then keep distributing so
(2x-1)(x-2)(x+1)
do each one seperately
do the first two first and put the other one (x+1) to the side for later
(2x-1)(x-2)=(2x-1)(x)+(2x-1)(-2)=(2x^2-x)+(-4x+2)=2x^2-5x+2
then do the other one
(x+1)(2x^2-5x+2)=(x)(2x^2-5x+2)+(1)(2x^2-5x+2)=(2x^3-5x^2+2x)+(2x^2-5x+2)=2x^3-3x^2-3x+2
the lasst form is 2x^3-3x^2-3x+2
Answer:
c. w = -1
Step-by-step explanation:
you have to add 2 with -3 and you get -1.
Answer:
yes
Step-by-step explanation:
