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pychu [463]
3 years ago
13

Which describes the adiabatic process? Check all that apply.

Physics
2 answers:
Colt1911 [192]3 years ago
8 0

Answer:

Heat is not absorbed by the system.

A rapid shift occurs between gas compression and expansion.

Explanation:

As we know by first law of thermodynamics

\Delta Q = \Delta U + W

here in case of adiabatic process we know that transfer of heat from the system must be zero

So here in that case

\Delta Q = 0

so here we will have

\Delta U + W = 0

so we have

\Delta U = - W

so the process must be very fast so that transfer of heat is not possible

so correct answer is

Heat is not absorbed by the system.

A rapid shift occurs between gas compression and expansion.

kiruha [24]3 years ago
7 0

Answer:

heat is not absorbed by the system

A rapid shift occurs between gas compression and expansion.

All heat is transformed to work done by the system.

Explanation:

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The best scientific reason for a scientist to accept a specific theory is?
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Answer:

The theory is supported by all the available observations and data.

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The amount of heat energy required to raise the temperature of a unit mass of a material one degree is
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The amount of heat energy required to raise the temperature of a unit mass of a material to one degree is called D. its heat capacity.

The relationship of the heat when applied to the object and the change in temperature of the object when heat is being applied is directly proportional to each other. This means that when heat is applied to the object, the temperature of the object increases and when heat is not applied to the object, the temperature of the object decreases.
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A cyclist going downhill is accelerating at 1.2 m/s2. If the final velocity of the cyclist is 16 m/s after 10 seconds, what is t
Blababa [14]

Answer:

Initial Velocity is 4 m/s

Explanation:

What is acceleration?

It is the change in velocity with respect to time, or the rate of change of velocity.

We can write this as:

a=\frac{\Delta v}{t}

Where

a is the acceleration

v is velocity

t is time

\Delta  is "change in"

For this problem , we are given

a = 1.2

t = 10

Putting into formula, we get:

a=\frac{\Delta v}{t}\\1.2=\frac{\Delta v}{10}\\\Delta v = 1.2*10\\\Delta v = 12

So, the change in velocity is 12 m/s

The change in velocity can also be written as:

\Delta v = Final  \ Velocity - Initial \ Velocity

It is given Final Velocity = 16, so we put it into formula and find Initial Velocity. Shown Below:

\Delta v = Final  \ Velocity - Initial \ Velocity\\12=16-Initial \ Velocity\\Initial \ Velocity = 16 - 12 = 4

hence,

Initial Velocity is 4 m/s

3 0
3 years ago
Read 2 more answers
Consider the motion of a 4.00-kg particle that moves with potential energy given by U(x) = + a) Suppose the particle is moving w
gtnhenbr [62]

Correct question:

Consider the motion of a 4.00-kg particle that moves with potential energy given by

U(x) = \frac{(2.0 Jm)}{x}+ \frac{(4.0 Jm^2)}{x^2}

a) Suppose the particle is moving with a speed of 3.00 m/s when it is located at x = 1.00 m. What is the speed of the object when it is located at x = 5.00 m?

b) What is the magnitude of the force on the 4.00-kg particle when it is located at x = 5.00 m?

Answer:

a) 3.33 m/s

b) 0.016 N

Explanation:

a) given:

V = 3.00 m/s

x1 = 1.00 m

x = 5.00

u(x) = \frac{-2}{x} + \frac{4}{x^2}

At x = 1.00 m

u(1) = \frac{-2}{1} + \frac{4}{1^2}

= 4J

Kinetic energy = (1/2)mv²

= \frac{1}{2} * 4(3)^2

= 18J

Total energy will be =

4J + 18J = 22J

At x = 5

u(5) = \frac{-2}{5} + \frac{4}{5^2}

= \frac{4-10}{25} = \frac{-6}{25} J

= -0.24J

Kinetic energy =

\frac{1}{2} * 4Vf^2

= 2Vf²

Total energy =

2Vf² - 0.024

Using conservation of energy,

Initial total energy = final total energy

22 = 2Vf² - 0.24

Vf² = (22+0.24) / 2

Vf = \sqrt{frac{22.4}{2}

= 3.33 m/s

b) magnitude of force when x = 5.0m

u(x) = \frac{-2}{x} + \frac{4}{x^2}

\frac{-du(x)}{dx} = \frac{-d}{dx} [\frac{-2}{x}+ \frac{4}{x^2}

= \frac{2}{x^2} - \frac{8}{x^3}

At x = 5.0 m

\frac{2}{5^2} - \frac{8}{5^3}

F = \frac{2}{25} - \frac{8}{125}

= 0.016N

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