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pychu [463]
4 years ago
13

Which describes the adiabatic process? Check all that apply.

Physics
2 answers:
Colt1911 [192]4 years ago
8 0

Answer:

Heat is not absorbed by the system.

A rapid shift occurs between gas compression and expansion.

Explanation:

As we know by first law of thermodynamics

\Delta Q = \Delta U + W

here in case of adiabatic process we know that transfer of heat from the system must be zero

So here in that case

\Delta Q = 0

so here we will have

\Delta U + W = 0

so we have

\Delta U = - W

so the process must be very fast so that transfer of heat is not possible

so correct answer is

Heat is not absorbed by the system.

A rapid shift occurs between gas compression and expansion.

kiruha [24]4 years ago
7 0

Answer:

heat is not absorbed by the system

A rapid shift occurs between gas compression and expansion.

All heat is transformed to work done by the system.

Explanation:

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Riders in a carnival ride stand with their backs against the wall of a circular room of diameter
Veseljchak [2.6K]

Answer:

option C

Explanation:

given,

diameter of circular room = 8 m

rotational velocity of the rider = 45 rev/min

                  = 45 \times \dfrac{2\pi}{60}

                  =4.712 rad/s

here in this case normal force is equal to centripetal force

N = m r ω²

N = m x 4 x 4.712²

N = 88.83m

frictional force = μ N

    = 88.83m x μ

now, for the body to not to slide

gravity force is equal to frictional force

m g = 88.83 m x μ

g = 88.83 x μ

9.8 = 88.83 x μ

 μ = 0.11

hence, the correct answer  is option C

6 0
4 years ago
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patriot [66]

Answer:

mark me brainlyest and ill answer

Explanation:

6 0
3 years ago
A 10,844.0 kg truck is initially at rest. The truck then accelerates across a level road and reaches a constant speed. It takes
lara [203]

Answer:

1,634.1 W

Explanation:

Power = work / time

P = 41,505.4 J / 25.4 s

P = 1,634.1 W

7 0
3 years ago
If 1.34 ✕ 1020 electrons move through a pocket calculator during a full day's operation, how many coulombs of charge moved throu
ioda

Given :

Number of operations move through a pocket calculator during a full day's operation , n=1.34 \times 10^{20} .

To Find :

How many coulombs of charge moved through it .

Solution :

We know , charge in  one electron is :

e^-=-1.6\times 10^{-19}\ coulombs

So , charge on n electron is :

C=e^-\times n\\C=-1.6\times 10^{-19}\times 1.34\times 10^{20} \ C\\C=-21.44\ C

Therefore , -21.44 coulombs of charge is moved through it .

Hence , this is the required solution .

3 0
3 years ago
What is the current in milliamperes produced by the solar cells of a pocket calculator through which 3.70 C of charge passes in
Kaylis [27]

Answer:

Current flowing in the cell will be equal to 0.1284 mA

Explanation:

We have given charge q = 3.70 C

And time through which charge is flowing = 8 hour

We know that 1 hour = 60 minutes, and 1 minute = 60 sec

So 1 hour = 60×60 = 3600 sec

So 8 hour = 8×3600 = 28800 sec

We know that current is rate time rate of flow of charge

So current i=\frac{q}{t}=\frac{3.70}{28800}=1.284\times 10^{-4}A=0.1284mA

So current flowing in the cell will be equal to 0.1284 mA

3 0
4 years ago
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