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3 years ago

What is the quadratic domain of y=x squared

Mathematics

1 answer:

statuscvo [17]3 years ago

4 0

domain is the numbes you are allowed to use for x

what I usually do is just find the numbers that aren't allowed in the domain. such numbers are numbers that cause a division by 0 or a squaer root of a negative number

given $y=x^2$ , there are no numbers that you can use for x that will cause a division by 0 or a square root of a negative number

so domain is all real numbers or D={x | -∞<x<∞}

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Write a linear function ff with f(4)=−3f(4)=−3 and f(0)=−2f(0)=−2

Nonamiya [84]

<span>The line goes through the points (4,-3) and (0,-2), so its gradient is (-2-(-3))/(0-4) = -1/4. The y-intercept is -2 because f(0)=-2. So the equation of the line is y = -1/4 x - 2.This can be represented by the linear function f(x) = (-1/4)x - 2. The composite function ff is given by ff(x) = f(-1/4 x - 2) = (-1/4)((-1/4)x - 2) - 2 = x/16 - 3/2.</span>

7 0

3 years ago

in 2009 Larry's gross pay was $275,800 in that year the maximum taxable for Social Security was 118500 and the Social Security w

zysi [14]

Based on the maximum taxable amount for social security in 2009, and the social security tax rate, the social security tax that Larry paid was $7,347.

<h3>How much did Larry pay in social security taxes?</h3>

The total amount paid by Larry as Social security tax can be found as;

= Maximum amount allowable for social security tax x Social security tax rate

The social security tax rate was 6.2% not 62.2%.

The social security tax was therefore:

= 118,500 x 6.2%

= $7,347

Find out more on social security taxes at brainly.com/question/13255138

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3 0

1 year ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection = </em>

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

Suppose milk is selling for 87.5¢ per litre. How many litres can you buy with $20?

lutik1710 [3]

3 becuse you put the numbers wrong

8 0

2 years ago

Please help. and Reduce to simpliest form. Thx <3

SCORPION-xisa [38]

Answer:

-11/8

Step-by-step explanation:

-7/8 - 1/2 = -11/8

3 0

3 years ago