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dsp73
3 years ago
9

Which Pair Of Compounds Are Isomers?

Chemistry
2 answers:
ruslelena [56]3 years ago
8 0
<span>The Pair Of Compounds that Are Isomers are CH3COCH3 and CH3CH2CHO. The answer is number 4. Isomers have the same formula but different structures. In number 4, both compounds contains three carbon atoms, one oxygen and 6 hydrogen atoms that makes them isomers.</span>
Kruka [31]3 years ago
4 0

Answer:  CH_3COCH_3 and CH_3CH_2CHO

Explanation:

The compounds having similar molecular formula but different arrangement of atoms or groups in space are called isomers and the phenomenon is called as isomerism.  

CH_3COCH_3 and CH_3CH_2CHO are functional isomers which have same molecular formula containing 3 carbon atoms, 6 hydrogen atoms and one oxygen atom each but different functional groups attached.

Rest compounds do not have similar molecular formulas.

Thus CH_3COCH_3 and CH_3CH_2CHO are isomers.

You might be interested in
Calculate the Ph and the POH of an aqueous solution that is 0. 040 m in HCl(aq) and 0. 075 m in HBr(aq) at 25 °C.
LenaWriter [7]

pH is the measure of the hydrogen ion concentration while pOH is of hydroxide ion concentration in the solution. The pH is 0.939 and pOH is 13.061 pOH.

pH is the concentration of the hydrogen ion released or gained by the species in the solution that depicts the acidity and basicity of the solution.

pOH is the concentration of the hydroxide ion in the solution and is dependent on the pH as an increase in pH decreases the pOH and vice versa.

Both HCl and HBr are strong acids and gets ionized 100 % in the solution. If we let 1 L of solution for the acids then the concentration of the hydrogen ion will be 0.100 M.

Since both completely dissociate we would just add the molarities of each of the H+ ions together and then calculate the PH and POH from that :

HCL(0.040M)----> H+(0.040M) +CL-(0.040M)

HBr(0.075M)----> H+(0.075M) +Br-(0.075M)

so 0.040M (H+ from HCL) + 0.075M (H+ from HBr) = 0.115M H+ in total.

pH is calculated as:

pH = -log[H+]

Substituting values in the equation:

log(0.115M)= 0.939 pH

pOH is calculated as:

14 - pH = pOH

Substituting values in the equation above:

14 - 0.939= 13.061 pOH

Therefore, pH is 0.939 and pOH is 13.061.

Learn more about pH and pOH here:

brainly.com/question/2947041

#SPJ4

5 0
2 years ago
What causes atoms to form covalent bonds?
tino4ka555 [31]

Sharing of valence electrons.

Explanation:

In a covalent bonds, there is sharing of the valence electrons used in bonding between the two combining species.

The atoms taking part do not have a wide electronegativity difference between them and so they share the valence electrons to complete their octet and ensure their stability.

  • For the formation of this bond type, each of the atom requires a odd or unpaired electrons.
  • Covalent bonds are formed between atoms having zero or very small electronegativity difference.

Learn more:

Covalent bonds brainly.com/question/10903097

#learnwithBrainly

6 0
3 years ago
What is the answer?
Dmitry_Shevchenko [17]

as a heterogeneous mixture

Explanation:

because I just know that it is

6 0
3 years ago
Erythrogenic acid, C18H26O2, is an acetylenic fatty acid that turns avivid red on exposure to light. On catalytic hydrogenation
lara31 [8.8K]

Answer:

use research

Explanation:

6 0
2 years ago
If we start with 8000 atoms of radium-226 how much would remain after 3200 years?
olya-2409 [2.1K]
<h3>Answer:</h3>

2000 atoms

<h3>Explanation:</h3>

We are given the following;

Initial number of atoms of radium-226 as 8000 atoms

Time taken for the decay 3200 years

We are required to determine the number of atoms that will remain after 3200 years.

We need to know the half life of Radium

  • Half life is the time taken by a radio active material to decay by half of its initial amount.
  • Half life of Radium-226 is 1600 years
  • Therefore, using the formula;

Remaining amount = Original amount × 0.5^n

where n is the number of half lives

n = 3200 years ÷ 1600 years

 = 2

Therefore;

Remaining amount = 8000 atoms × 0.5^2

                                = 8000 × 0.25

                                 = 2000 atoms

Thus, the number of radium-226 that will remain after 3200 years is 2000 atoms.

6 0
3 years ago
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