Question

If a 990 kg car is on the road and the Ff is 360 n what is the normal force

Answer 1

Given that a car is in the road, there is only movement in the x-direction. There is no movement in the y-direction.

Looking at the y-direction for the normal force:

F = N - mg
0 = N - mg, (no movement in y-dir.)
N = mg
N = (990)(9.8)
N = 9702 newtons

The normal force exerted on the car by the road is 9702 newtons.

Answer 2

Answer:

9700 N upward

Explanation:

Got right on my test.