Answer:
The relationship is only between the coefficients A, E and J which is:
. The remaining coefficients can be anything without any constraints.
Explanation:
Given:
The three components of velocity is a velocity field are given as:
The fluid is incompressible.
We know that, for an incompressible fluid flow, the sum of the partial derivatives of each component relative to its direction is always 0. Therefore,
Now, let us find the partial derivative of each component.
Hence, the relationship between the coefficients is:
There is no such constraints on other coefficients. So, we can choose any value for the remaining coefficients B, C, D, F, G and H.
The centripetal acceleration is responsible
for the artificial gravity because the acceleration of an object moving in constant
circular motion causing from net external force is called centripetal
acceleration. It defines to the center or seeking the center.
Given the following:
Cylindrical space station
diameter = 275 meters; 137.5
meters for the radius
Standard gravity =
9.80665 m/s²
Using the formula:
w² x r =g
w² = g / r
w² = 9.80665 m/s²
/ 137.5 m
w² = 9.80665 m/s²
/ 137.5 m
w² = 0.0713 s²
Then take the roots
w = 0.267 this is radians per
second / 2 x (3.1416 which is the pi)
w = 0.0424 rps convert to rpm
w = 0.0424 r/s (1minute / 60
seconds)
w = 7.08 x 10⁻⁴ revolutions per minute
65 years but anything can happen to them
I’m not really sure but I hope this helps
Kinetic energy = (1/2) (mass) (speed)²
BUT . . . in order to use this equation just the way it's written,
the speed has to be in meters per second. So we'll have to
make that conversion.
KE = (1/2) · (1,451 kg) · (48 km/hr)² · (1000 m/km)² · (1 hr/3,600 sec)²
= (725.5) · (48 · 1000 · 1 / 3,600)² (kg) · (km·m·hr / hr·km·sec)²
= (725.5) · ( 40/3 )² · ( kg·m² / sec²)
= 128,978 joules (rounded)
Answer:
A) μ = A.m²
B) z = 0.46m
Explanation:
A) Magnetic dipole moment of a coil is given by; μ = NIA
Where;
N is number of turns of coil
I is current in wire
A is area
We are given
N = 300 turns; I = 4A ; d =5cm = 0.05m
Area = πd²/4 = π(0.05)²/4 = 0.001963
So,
μ = 300 x 4 x 0.001963 = 2.36 A.m².
B) The magnetic field at a distance z along the coils perpendicular central axis is parallel to the axis and is given by;
B = (μ_o•μ)/(2π•z³)
Let's make z the subject ;
z = [(μ_o•μ)/(2π•B)] ^(⅓)
Where u_o is vacuum permiability with a value of 4π x 10^(-7) H
Also, B = 5 mT = 5 x 10^(-6) T
Thus,
z = [ (4π x 10^(-7)•2.36)/(2π•5 x 10^(-6))]^(⅓)
Solving this gives; z = 0.46m =
