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Julli [10]
3 years ago
11

What are non examples of light years?

Physics
2 answers:
abruzzese [7]3 years ago
5 0
Hi , here are some examples: An astronomical unit A parsec A meter
Gennadij [26K]3 years ago
4 0
<span>a parsec is not a light year: 31 trillion (3.1×1013) kilometres (about 19 trillion miles).

an astronomical Unit: 149,597,870.7 kilometers (92,955,807.27 miles) - the average distance from the sun to the earth</span>
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Help and explain thanks
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Answer:

the faster an object moves the more kinetic it has. the more mass an object has, the more kinetic energy it has.

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2 years ago
On the ____ scale, an increase of ten dicibels means an intensity increases of ten times.
UkoKoshka [18]

Answer:

the answer is decibel

7 0
3 years ago
(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 3
Lelu [443]

Complete question:

(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 330 kJ/kg. The initial temperature of the water is 20 ⁰C

Answer:

The energy that must be supplied to boil the given mass of the water is 672,000 J

Explanation:

Given;

mass of water, m = 2 kg

heat of vaporization of water, L =  330 kJ/kg

initial temperature of water, t = 20 ⁰C

specific heat capacity of water, c = 4200 J/kg⁰C

Assuming no mass of the water is lost through vaporization, the energy needed to boil the given water is calculated as;

Q = mc(100 - 20)

Q = 2 x 4200 x (80)  

Q = 672,000 J

Q = 672,000 J

Q = 672,000 J

Therefore, the energy that must be supplied to boil the given mass of the water is 672,000 J

8 0
3 years ago
Two 2 kg masses is placed at either end of a rod that has a mass of .5 kg and a length of 3 m. What is the moment of inertia if
sergij07 [2.7K]

Explanation:

a) I=\displaystyle \sum_{i}m_ir_i^2

where r_i is the distance of the mass m_i from the axis of rotation. When the axis of rotation is placed at the end of the rod, the moment of inertia is due only to one mass. Therefore,

I= mr^2 = (2\:kg)(3\:m)^2 = 18\:kg-m^2

b) When the axis of rotation is placed on the center of the rod, the moment is due to both masses and the radius r is 1.5 m. Therefore,

\displaystyle I= \sum_{i}m_ir_i^2 = 2(2\:kg)(1.5\:m)^2 = 9\:kg-m^2

7 0
3 years ago
Consider two adjacent states, S1 and S2, that wish to control particulate emissions from power plants and cement plants; New Jer
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Answer:

a. 7500

b. Yes

c. 2500

d. 7500

Explanation:

Please see attachment

7 0
3 years ago
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