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Julli [10]
3 years ago
11

What are non examples of light years?

Physics
2 answers:
abruzzese [7]3 years ago
5 0
Hi , here are some examples: An astronomical unit A parsec A meter
Gennadij [26K]3 years ago
4 0
<span>a parsec is not a light year: 31 trillion (3.1×1013) kilometres (about 19 trillion miles).

an astronomical Unit: 149,597,870.7 kilometers (92,955,807.27 miles) - the average distance from the sun to the earth</span>
You might be interested in
Help. I need to find the degree using the sine law.
Marina CMI [18]
Use pythagorean theorem
a ^{2}  + b {}^{2}  = c {}^{2}
to find the opposite side, which is 7.3

so then you can just use inverse sinA=7.3/10 which equals 46.9 degrees
4 0
3 years ago
What distance is covered by an airplane traveling at a velocity of 660 miles per hour in 3.5 hours?
N76 [4]

As per the question, the velocity of the airplane [v] = 660 miles per hour.

The total time taken by airplane [t] = 3.5 hours.

We are asked to determine the total distance travelled by the airplane during that period.

The distance covered [ S] by a body is the product of velocity with the time.

Mathematically distance covered = velocity × total time

                                                      S = v × t

                                                        = 660 miles/hour ×3.5 hours

                                                        = 2310 miles.

Hence, the total distance travelled by the airplane in 3.5 hour is 2310 miles.

4 0
2 years ago
g stAn experienced spear fisherman sees a small fish swimming in a tidal pool. If the fisherman sees the fish at approximately a
Luba_88 [7]

Answer:

  θ = 28.9

Explanation:

For this exercise let's use the law of refraction

          n₁ sin θ₁ = n₂ sin θ₂

where we use index 1 for air and index 2 for water where the fish is

        sin θ₂ = n₁ / n₂ sin θ₁

in this case the air repair index is 1 and the water 1.33

we substitute

        sin θ₂ = 1 / 1.33 sin t 40

        sin θ = 0.4833

         

        θ = sin⁻¹ 0.4833

        θ = 28.9

5 0
3 years ago
In attempting to pass the puck to a teammate, a hockey player gives it an initial speed of 2.8 m/s. However, this speed is inade
erastova [34]

Answer:

3.95979 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow as=\frac{v^2-u^2}{2}\\\Rightarrow as=\frac{0^2-2.8^2}{2}\\\Rightarrow as=-3.92

Here s=\frac{1}{2}s

\\\Rightarrow as=-7.84\ m/s^2

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -7.84}\\\Rightarrow u=3.95979\ m/s

Initial velocity of the puck should be 3.95979 m/s

8 0
2 years ago
***FIRST CORRECT ANSWER GETS A BRAINLIEST***
melomori [17]

Answer:

Explanation: It is halved

3 0
3 years ago
Read 2 more answers
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