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Julli [10]
3 years ago
11

What are non examples of light years?

Physics
2 answers:
abruzzese [7]3 years ago
5 0
Hi , here are some examples: An astronomical unit A parsec A meter
Gennadij [26K]3 years ago
4 0
<span>a parsec is not a light year: 31 trillion (3.1×1013) kilometres (about 19 trillion miles).

an astronomical Unit: 149,597,870.7 kilometers (92,955,807.27 miles) - the average distance from the sun to the earth</span>
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Once a well has reached the water table, it will not run dry true or false? -earth science
prohojiy [21]
No, this is false.

In principle, every well can run dry, and this includes a well that has reached the water table. If the water is taken from the well faster than it's replenishing itself, the well will run dry- and in this situation, typically people need to look for a new place to have a well.
3 0
4 years ago
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An ice skater has a moment of inertia of 5.0 kgm2 when her arms are outstretched. at this time she is spinning at 3.0 revolution
givi [52]
With arms outstretched,
Moment of inertia is I = 5.0 kg-m².
Rotational speed is ω = (3 rev/s)*(2π rad/rev) = 6π rad/s
The torque required is
T = Iω = (5.0 kg-m²)*(6π rad/s) = 30π 

Assume that the same torque drives the rotational motion at a moment of inertia of 2.0 kg-m².
If u = new rotational speed (rad/s), then
T = 2u = 30π
u = 15π rad/s
   = (15π rad/s)*(1 rev/2π rad)
   = 7.5 rev/s

Answer: 7.5  revolutions per second.

7 0
4 years ago
What is the angle between the incident ray and the normal ray called?
alisha [4.7K]

Answer:

A, the angle of refraction

8 0
4 years ago
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A 25 N force at 60° is required to set a crate into motion on a floor. What is the value of the static friction?
True [87]
The normal force of the force given is calculated through the equation,
 
                                 Fn = F(sin θ)
where Fn is the normal force, F is the force, and θ is the angle. 
  
                                Fn = (25 N)(sin 60°) = 21.65 N

The x-component of the force applied is,
                               Fx = (25 N)(cos 60°) = 12.5 N

The value of the coefficient of static friction is calculated through the equation,
                              F = μFn
                              μ = Fx / Fn = 12.5 N / 21.65 N = 0.577
3 0
3 years ago
In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is appro
Alexxx [7]

Explanation:

It is given that,

Radius of the circular orbit, r=0.53\times 10^{-10}\ m  

Speed of the electron, v=2.2\times 10^6\ m/s

Mass of the electron, m=9.1\times 10^{-31}\ kg

(a) The force acting on the electron is centripetal force. Its formula is given by :

F=\dfrac{mv^2}{r}

F=\dfrac{9.1\times 10^{-31}\times (2.2\times 10^6)^2}{0.53\times 10^{-10}}  

F=8.31\times 10^{-8}\ N

(b) The centripetal acceleration of the electron is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(2.2\times 10^6)^2}{0.53\times 10^{-10}}

a=9.13\times 10^{22}\ m/s^2

Hence, this is the required solution.

5 0
3 years ago
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