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dlinn [17]
3 years ago
6

How long would a 2950 N force need to act to cause a 6000 kg delivery truck to accelerate from 4.0m/s to 29.0m/s?​

Physics
1 answer:
AysviL [449]3 years ago
8 0

Answer:

Time, t = 50.8 seconds.

Explanation:

Given the following data;

Mass = 6000 kg

Force = 2950 N

Initial velocity = 4 m/s

Final velocity = 29 m/s

To find time;

First of all, we would determine the acceleration of the truck using the following formula;

Force = mass * acceleration

2950 = 6000 * acceleration

Acceleration = 2950/6000

Acceleration = 0.492 m/s²

Next, we find time using the first equation of motion;

V = U + at

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Making time, t the subject of formula, we have;

t = \frac{V - U}{a}

Substituting into the equation, we have;

t = \frac{29 - 4}{0.492}

t = \frac{25}{0.492}

Time, t = 50.8 seconds.

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a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s .The amplitude of the subsequent oscillations 48.13 cm/s

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To learn more about oscillations Please click on the given link:

brainly.com/question/26146375

#SPJ4

This is incomplete question Complete Question is:

a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s . what are The amplitude of the subsequent oscillations?

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