How long would a 2950 N force need to act to cause a 6000 kg delivery truck to accelerate from 4.0m/s to 29.0m/s?
1 answer:
Answer:
Time, t = 50.8 seconds.
Explanation:
Given the following data;
Mass = 6000 kg
Force = 2950 N
Initial velocity = 4 m/s
Final velocity = 29 m/s
To find time;
First of all, we would determine the acceleration of the truck using the following formula;
Force = mass * acceleration
2950 = 6000 * acceleration
Acceleration = 2950/6000
Acceleration = 0.492 m/s²
Next, we find time using the first equation of motion;
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
Making time, t the subject of formula, we have;
Substituting into the equation, we have;
Time, t = 50.8 seconds.
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Answer:
570 N
Explanation:
Draw a free body diagram on the rider. There are three forces: tension force 15° below the horizontal, drag force 30° above the horizontal, and weight downwards.
The rider is moving at constant speed, so acceleration is 0.
Sum of the forces in the x direction:
∑F = ma
F cos 30° - T cos 15° = 0
F = T cos 15° / cos 30°
Sum of the forces in the y direction:
∑F = ma
F sin 30° - W - T sin 15° = 0
W = F sin 30° - T sin 15°
Substituting:
W = (T cos 15° / cos 30°) sin 30° - T sin 15°
W = T cos 15° tan 30° - T sin 15°
W = T (cos 15° tan 30° - sin 15°)
Given T = 1900 N:
W = 1900 (cos 15° tan 30° - sin 15°)
W = 570 N
The rider weighs 570 N (which is about the same as 130 lb).
