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dlinn [17]
3 years ago
6

How long would a 2950 N force need to act to cause a 6000 kg delivery truck to accelerate from 4.0m/s to 29.0m/s?​

Physics
1 answer:
AysviL [449]3 years ago
8 0

Answer:

Time, t = 50.8 seconds.

Explanation:

Given the following data;

Mass = 6000 kg

Force = 2950 N

Initial velocity = 4 m/s

Final velocity = 29 m/s

To find time;

First of all, we would determine the acceleration of the truck using the following formula;

Force = mass * acceleration

2950 = 6000 * acceleration

Acceleration = 2950/6000

Acceleration = 0.492 m/s²

Next, we find time using the first equation of motion;

V = U + at

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Making time, t the subject of formula, we have;

t = \frac{V - U}{a}

Substituting into the equation, we have;

t = \frac{29 - 4}{0.492}

t = \frac{25}{0.492}

Time, t = 50.8 seconds.

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2 years ago
In a charging process, 1 × 10^13 electrons are removed from one small metal sphere and placed on a second identical sphere. Init
liraira [26]

Answer:

r = 0.303m

= 30.3cm

Explanation:

Given that,

The number of electrons transferred from one sphere to the other,  

n  = 1 ×10 ¹³e le c t r o n s

The electrostatic potential energy between the spheres,  

U = − 0.061 J

The charge on an electron,  

q = − 1.6 × 10 ⁻¹⁹C

The coulomb constant,  

K = 8.98755 × 10 ⁹ N ⋅ m ² / C 2²

Due to the transfer of electrons, both spheres become equally and oppositely.

The charge gained by the sphere due to the excess of the electron is:  

q ₁ = n q

   = 1 ×10 ¹³ *  − 1.6 × 10 ⁻¹⁹

   = -1.6  × 10⁻⁶C

The charge left on the first sphere is =

q ₂ = -q₁ = 1.6  × 10⁻⁶C

The electric potential energy between two point charges is given by the following equation:

U = K q ₁q ₂/r

q ₁ and  q ₂ are the two charges.

r  is the distance between the charge and the point.

K  =  8.98755  ×  10 ⁹ N ⋅ m ² / C ²

we have:

-0.061 =  (8.98755  ×  10 ⁹ * (-1.6  × 10⁻⁶)²) / r

r = (18.41 ×  10 ⁻³) / 0.061

r = 0.303m

= 30.3cm

4 0
3 years ago
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