How long would a 2950 N force need to act to cause a 6000 kg delivery truck to accelerate from 4.0m/s to 29.0m/s?
1 answer:
Answer:
Time, t = 50.8 seconds.
Explanation:
Given the following data;
Mass = 6000 kg
Force = 2950 N
Initial velocity = 4 m/s
Final velocity = 29 m/s
To find time;
First of all, we would determine the acceleration of the truck using the following formula;
Force = mass * acceleration
2950 = 6000 * acceleration
Acceleration = 2950/6000
Acceleration = 0.492 m/s²
Next, we find time using the first equation of motion;
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
Making time, t the subject of formula, we have;
Substituting into the equation, we have;
Time, t = 50.8 seconds.
You might be interested in
Answer:
- Voltage=V=120V
- Power=P=60W
- Current=I
Answer:
The <em><u>n = 2 → n = 3</u></em> transition results in the absorption of the highest-energy photon.
Explanation:
Formula used for the radius of the orbit will be,
where,
= energy of
orbit
n = number of orbit
Z = atomic number
Here: Z = 1 (hydrogen atom)
Energy of the first orbit in H atom .
Energy of the second orbit in H atom .
Energy of the third orbit in H atom .
Energy of the fifth orbit in H atom .
Energy of the sixth orbit in H atom .
Energy of the seventh orbit in H atom .
During an absorption of energy electron jumps from lower state to higher state.So, absorption will take place in :
1) n = 2 → n = 3
2) n= 5 → n = 6
Energy absorbed when: n = 2 → n = 3
Energy absorbed when: n = 5 → n = 6
1.89 eV > 0.166 eV
E> E'
So,the n = 2 → n = 3 transition results in the absorption of the highest-energy photon.