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dlinn [17]
3 years ago
6

How long would a 2950 N force need to act to cause a 6000 kg delivery truck to accelerate from 4.0m/s to 29.0m/s?​

Physics
1 answer:
AysviL [449]3 years ago
8 0

Answer:

Time, t = 50.8 seconds.

Explanation:

Given the following data;

Mass = 6000 kg

Force = 2950 N

Initial velocity = 4 m/s

Final velocity = 29 m/s

To find time;

First of all, we would determine the acceleration of the truck using the following formula;

Force = mass * acceleration

2950 = 6000 * acceleration

Acceleration = 2950/6000

Acceleration = 0.492 m/s²

Next, we find time using the first equation of motion;

V = U + at

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Making time, t the subject of formula, we have;

t = \frac{V - U}{a}

Substituting into the equation, we have;

t = \frac{29 - 4}{0.492}

t = \frac{25}{0.492}

Time, t = 50.8 seconds.

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Answer:

The mass of the ice added = 16.71 g

Explanation:

The heat gained by the ice is equal to the heat lost by the calorimeter cup and the water in the cup.

But for this question, the cup is said to be perfectly insulated, hence, there is no loss of heat from the calorimeter cup.

Heat gained by the ice = Heat lost by the 326 g of water.

Let the mass of ice be m

The heat gained by the ice = (Heat gained by ice in temperature from -5.5°C to 0°C) + (Heat used by the ice to melt at 0°C) + (Heat required for the melted ice to rise in temperature from 0°C to 15°C)

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Heat used by the ice to melt at 0°C = m×334 = (334m) J

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Heat lost by the water in the calorimeter cup = MCΔT

M = mass of water in the calorimeter cup = 326 g

C = specific heat capacity of water = 4.186 J/g°C

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408.384m = 6,823.18

m = (6,823.18/408.384)

m = 16.71 g

Hope this Helps!!!

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