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2 years ago

The attraction of liquid particles for a solid surface is due to ____.

Physics

2 answers:

Kisachek [45]2 years ago

8 0

Answer:

the force of adhesion.

Explanation:

The attractive force between the two types of molecules is called adhesive force.

So, the force between the liquid molecule and the solid molecule is adhesive in nature.

The attractive force acts between the two same type of molecules is called cohesive force.

White raven [17]2 years ago

6 0

This attraction occurs from adhesion, also known as adsorption <span />

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In moving out of a dormitory at the end of the semester, a student does 1.82 x 104 J of work. In the process, his internal energ

emmainna [20.7K]

Answer:

Explanation:

(a) Work done, W = 1.82 x 10^4 J

(b) internal energy, U = - 4.07 x 10^4 J ( as it decreases)

Q = W + U

Q = 1.82 x 10^4 - 4.07 x 10^4

Q = - 2.25 x 10^4 J

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3 years ago

what is the valure of work done on an objectwhen a 50newton force moves it 15 metrs in thesame dirction as the force

Snowcat [4.5K]

50 *15=750
work is force time distance times angle between both vectors
here the angle is 0.

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3 years ago

The ???? ,of an object is a vector that is directed toward<br> the center of the Earth.

Aleks04 [339]

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2 years ago

How much force (in Newtons) acts on a 1700 kg car going around a

Daniel [21]

Answer:

b) 4781 N

Explanation:

Because there is a redius do this question is talking about the acceleration force which= mv^2/r

so a=15^2/80=2.8125 m^2/s

so the force will be = m.a

F =1700×2.8125=4781.25 N

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2 years ago

The current through an inductor of inductance L is given by I(t) = Imax sin(ωt).

sammy [17]

Answer:

(a) $emf_L=-LI_{max}\omega cos(\omega t)$

(b) neither increasing or decreasing

Explanation:

The current through an inductor of inductance L is given by:

$I(t)=I_{max}sin(\omega t)$ (1)

(a) The induced emf is given by the following formula

$emf_L=-L\frac{dI}{dt}$ (2)

You derivative the expression (1) in the expression (2):

$emf_L=-L\frac{d}{dt}(I_{max}sin(\omega t))\\\\emf_L=-LI_{max}\omega cos(\omega t)$

(b) At t=0 the current is zero

(c) At t = 0 the emf is:

$emf_L=-\omega LI_{max}$

w, L and Imax have positive values, then the emf is negative. Hence, the induced emf is opposite to the flow of the charge carriers.

(d) read the text carefully

6 0

2 years ago