Answer:
The compression of the spring is 24.6 cm
Explanation:
magnitude of the charge on the left, q₁ = 4.6 x 10⁻⁷ C
magnitude of the charge on the right, q₂ = 7.5 x 10⁻⁷ C
distance between the two charges, r = 3 cm = 0.03 m
spring constant, k = 14 N/m
The attractive force between the two charges is calculated using Coulomb's law;

The extension of the spring is calculated as follows;
F = kx
x = F/k
x = 3.45 / 14
x = 0.246 m
x = 24.6 cm
The compression of the spring is 24.6 cm
Answer:
Pressure = 320 N/m²
Explanation:
Given the following data;
Force = 8000 Newton
Area = 25 m²
To find the pressure, we would use the following formula;
Pressure = force/area
Substituting into the formula, we have;
Pressure = 8000/25
Pressure = 320 N/m²
Answer:
0.4
Explanation:

kinetic energy formula , potential energy is not considered
0.5×0.2×2×2
The force = 0.3 * 9.8 = 2.94
x = 0.13
k = 2.94/0.13
k = 22.6 N/m