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spayn [35]
2 years ago
14

A positively charged particle of certain mass may be suspended (at rest) in electric field of suitable strength if the field is

directed
a)outward
b)inward
c)downward
d)upward
Physics
1 answer:
Studentka2010 [4]2 years ago
5 0

If the electric field is directed d) upward

Explanation:

In order for a positively charged particle to be suspended at rest, the electric force due to the electric field must be

1) equal in magnitude, and

2) opposite in direction

to the force of gravity acting on the particle. Since the force of gravity acts downward, the electric force must be upward. The electric force on a charged particle is given by

F=qE

where

q is the charge

E is the electric field

And the direction of the force is:

  • The  same as the electric field for a positive charge
  • Opposite to the direction of the field for a negative charge

Here we have a positive charge, therefore the direction of the electric field must be the same as the direction of the force, therefore upward.

Learn more about electric field:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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A push or pull that causes an object's motion to change is called _____
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Answer:

Force

Explanation:

Force is a pull or push that causes An objects motion to change . When force is applied to an object , it either pushes the object to or pulls it from something thereby changing the motion of the object. A good example is the earth’s gravitational force. This force pulls or attracts a body to the center of the earth . Another example Is experienced when kicking a football from one part of a football field to another. The ball is kicked with force and this causes it to move from one place another .

6 0
3 years ago
2) Two railway tracks are parallel to west east direction. Along one track, train A moves with a speed of 45 m/s from
OLEGan [10]

Answer:

Relative\ Velocity = 105m/s

Explanation:

Given

V_A = 45m/s

V_B = 60m/s

Required

Determine the speed of B w.r.t A

The question implies that, we determine the relative velocity of B w.r.t A

Because both trains are moving towards one another, the required velocity is a sum\ of\ velocities\ of both trains:

This is shown below:

Relative\ Velocity = V_A + V_B

Relative\ Velocity = 45m/s + 60m/s

Relative\ Velocity = 105m/s

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3 years ago
What Is the acceleration of a toy car that starts from rest and has a speed of 0.12 m/s after 0.1?
VikaD [51]

Given: Initial velocity of toy car (u ) = 0

Final velocity of toy car (v) = 0.12 m/s

Required time (t) = 0.1 s

To find: The acceleration of the toy car.

Let the acceleration of the toy car be (a)

Formula Used: 1st kinematic equation of motion

                              v = u + at ---------------------------(i)

Here, all alphabets are in their usual meanings

Now, from equation (i), we shall calculate the value of 'a'.

so,                          a = (v - u) /t

or,                          a = (0.12 m/s - 0) / 0.1s

or,                          a = 1.2 m/s²

Hence, the required acceleration of the toy car will be 1.2 m/s².

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bagirrra123 [75]

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