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spayn [35]
2 years ago
14

A positively charged particle of certain mass may be suspended (at rest) in electric field of suitable strength if the field is

directed
a)outward
b)inward
c)downward
d)upward
Physics
1 answer:
Studentka2010 [4]2 years ago
5 0

If the electric field is directed d) upward

Explanation:

In order for a positively charged particle to be suspended at rest, the electric force due to the electric field must be

1) equal in magnitude, and

2) opposite in direction

to the force of gravity acting on the particle. Since the force of gravity acts downward, the electric force must be upward. The electric force on a charged particle is given by

F=qE

where

q is the charge

E is the electric field

And the direction of the force is:

  • The  same as the electric field for a positive charge
  • Opposite to the direction of the field for a negative charge

Here we have a positive charge, therefore the direction of the electric field must be the same as the direction of the force, therefore upward.

Learn more about electric field:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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Two people carry a heavy electric motor by placing it on a light board 1.80 m long. One person lifts at one end with a force of
bixtya [17]

Answer:

W=970\ N

Explanation:

When two people carry a weight placing it on a very light board then we neglect the weight of the board and the board acts like a beam with two mass placed over it and two end point supports are here provided by men.

Then balancing the forces in the vertical direction, weight of the motor is:

W=350+620

W=970\ N

These men are able to carry the motor in equilibrium condition because they have placed the motor (considering it a point mass) at a position such that the moment due to the lifting forces are equal and opposite.

6 0
3 years ago
What information did mendeleev have about the elements he organized into a periodic table
Andrej [43]
He had their masses and reactivity. I hope this helps.
3 0
3 years ago
How many seconds have you been alive? If your 16
kolbaska11 [484]
504921600 seconds. Hope this helps!
3 0
2 years ago
A tennis ball rolls off the edge of a table. the table is 0.55m tall and the tennis ball lands 0.12m away from the table.
k0ka [10]

Answer:

v = 0.363 m/s

Explanation:

Given that,

The table is 0.55m tall and the tennis ball lands 0.12m away from the table.

Here, u = 0 (at rest) for initial vertical velocity as it rolls off the edge of a table.

Let t is the time to fall from the vertical height. So,

h=ut+\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 0.55}{9.8}} \\\\t=0.33\ s

It can be assumed to find the initial horizontal velocity of the tennis ball. It can be given by :

v_x=\dfrac{x}{t}\\\\v_x=\dfrac{0.12}{0.33}\\\\v_x=0.363\ m/s

Hence, the initial horizontal velocity is 0.363 m/s.

3 0
3 years ago
A horse trots 17 miles north and then turns and trots 24 miles at an angle of 40° west of north. Find the resultant displacement
DanielleElmas [232]

Answer:

 Resultant displacement = 38.58 miles at an angle of 23.57° north of west.

Explanation:

Let north represent positive y direction and east represent positive x direction. Unit vector along x direction is represented by i and vector along unit vector along y direction is represented by j

Initial displacement = 17 miles north = 17 j miles

Final displacement = 24 miles at an angle of 40° west of north = 24 miles at an angle of 130° to positive x -axis

                               = (24 cos 130 i + 24 sin 130 j )

                               = (-15.43 i + 18.36 j ) miles

Total displacement = 17 j + (-15.43 i + 18.36 j) = -15.43 i + 35.36 j

Magnitude of displacement =\sqrt{(-15.43)^2+35.36^2} =38.58 miles

Angle to positive x -axis = tan⁻¹(35.36/-15.43) = 113.57°

Resultant displacement = 38.58 miles at an angle of 23.57° west of north.

8 0
3 years ago
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