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spayn [35]
2 years ago
14

A positively charged particle of certain mass may be suspended (at rest) in electric field of suitable strength if the field is

directed
a)outward
b)inward
c)downward
d)upward
Physics
1 answer:
Studentka2010 [4]2 years ago
5 0

If the electric field is directed d) upward

Explanation:

In order for a positively charged particle to be suspended at rest, the electric force due to the electric field must be

1) equal in magnitude, and

2) opposite in direction

to the force of gravity acting on the particle. Since the force of gravity acts downward, the electric force must be upward. The electric force on a charged particle is given by

F=qE

where

q is the charge

E is the electric field

And the direction of the force is:

  • The  same as the electric field for a positive charge
  • Opposite to the direction of the field for a negative charge

Here we have a positive charge, therefore the direction of the electric field must be the same as the direction of the force, therefore upward.

Learn more about electric field:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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Outside our solar system the closest star to earth is Proxima century life from the start takes 2200000 minutes to reach earth.
s2008m [1.1K]

Answer:

2200000 = 2.2E6 min for light from Proxima to reach earth

8.3 min from light sun to reach earth

2.2E6/8.3 = 2.56E5   times for light from Proxima

Proxima is about 256,000 times farther away than the sun

Since the sun is about 93,000,000 = 9.3E7 miles from earth

Proxima is then 9.3E7 * 2.56E5 = 2.4E13 miles away

Note - the speed of light is

3.00E8 m/s * 60 s/min / 1000 m/km = 1.8E7 km/min as given

5 0
2 years ago
A 13,000-N vehicle is to be lifted by a 25-cm diameter hydraulic piston. What force needs to be applied to a 5.0 cm diameter pis
MaRussiya [10]

Answer:

Explanation:

We shall apply Pascal's Law in fluid mechanics

According to it , pressure is transmitted in liquid from one point to another without any change .

25 cm diameter = 12.5 x 10⁻² m radius

Area = 3.14 x (12.5 x 10⁻²)²

= 490.625 x 10⁻⁴ m²

Pressure by vehicle

Force / area

13000 / 490.625 x 10⁻⁴

= 26.497 x 10⁴ Pa

5 cm diameter = 2.5 x 10⁻² radius

area = 3.14 x (2.5 x 10⁻²)²

= 19.625 x 10⁻⁴ m²

If we assume required force F on this area

Pressure = F / 19.625 x 10⁻⁴ Pa

According to Pascal Law

F / 19.625 x 10⁻⁴  = 26.497 x 10⁴

F = 19.625 x 26.497

= 520 N

4 0
3 years ago
Miss Hu taught her class what makes night and day on Earth. She could not use the real Sun. She used a light bulb instead. In th
kherson [118]

B. model; it is the model of the sun

5 0
2 years ago
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An electromagnet is strong enough to lift 200 kg of mass. If you double the number of turns of wire around the core and triple t
VLD [36.1K]

Answer:1200 kg

Explanation:

Given

Electromagnet can lift a mass of  200\ kg

Magnetic force necessary to hold mass is proportional to Magnetic field

and magnetic field (B) is proportional to NIA

where N=no of turns

I=current in the magnet

A=area of cross-section

When we double the no of turns and triple the current then

N becomes 2 N

I becomes 3 I

therefore magnetic field becomes 6 times

Thus magnetic force becomes 6 times and we can say that electromagnet can hold the 6 times of given weight

i.e. 6\times 200=1200\ kg

4 0
3 years ago
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Yes I am subscribed to coryxkenshin but are you subscribed to me jp
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