A positively charged particle of certain mass may be suspended (at rest) in electric field of suitable strength if the field is
1 answer:
If the electric field is directed d) upward
Explanation:
In order for a positively charged particle to be suspended at rest, the electric force due to the electric field must be
1) equal in magnitude, and
2) opposite in direction
to the force of gravity acting on the particle. Since the force of gravity acts downward, the electric force must be upward. The electric force on a charged particle is given by
where
q is the charge
E is the electric field
And the direction of the force is:
- The same as the electric field for a positive charge
- Opposite to the direction of the field for a negative charge
Here we have a positive charge, therefore the direction of the electric field must be the same as the direction of the force, therefore upward.
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Answer:
141.78 ft
Explanation:
When speed, u = 44mi/h, minimum stopping distance, s = 44 ft = 0.00833 mi.
Calculating the acceleration using one of Newton's equations of motion:
Note: The negative sign denotes deceleration.
When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2
Hence, we can find the minimum stopping distance using:
The minimum stopping distance is 141.78 ft.