A positively charged particle of certain mass may be suspended (at rest) in electric field of suitable strength if the field is
1 answer:
If the electric field is directed d) upward
Explanation:
In order for a positively charged particle to be suspended at rest, the electric force due to the electric field must be
1) equal in magnitude, and
2) opposite in direction
to the force of gravity acting on the particle. Since the force of gravity acts downward, the electric force must be upward. The electric force on a charged particle is given by
where
q is the charge
E is the electric field
And the direction of the force is:
- The same as the electric field for a positive charge
- Opposite to the direction of the field for a negative charge
Here we have a positive charge, therefore the direction of the electric field must be the same as the direction of the force, therefore upward.
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Answer:
0.786 Hz, 1.572 Hz, 2.358 Hz, 3.144 Hz
Explanation:
The fundamental frequency of a standing wave on a string is given by
where
L is the length of the string
T is the tension in the string
is the mass per unit length
For the string in the problem,
L = 30.0 m
T = 20.0 N
Substituting into the equation, we find the fundamental frequency:
The next frequencies (harmonics) are given by
with n being an integer number and f being the fundamental frequency.
So we get: