A positively charged particle of certain mass may be suspended (at rest) in electric field of suitable strength if the field is
1 answer:
If the electric field is directed d) upward
Explanation:
In order for a positively charged particle to be suspended at rest, the electric force due to the electric field must be
1) equal in magnitude, and
2) opposite in direction
to the force of gravity acting on the particle. Since the force of gravity acts downward, the electric force must be upward. The electric force on a charged particle is given by
where
q is the charge
E is the electric field
And the direction of the force is:
- The same as the electric field for a positive charge
- Opposite to the direction of the field for a negative charge
Here we have a positive charge, therefore the direction of the electric field must be the same as the direction of the force, therefore upward.
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The magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair is 198 Newton.
<u>Given the following data:</u>
- Mass of cat = 2 kg
- Mass of elevator = 97 kg
- Acceleration = 2
To determine the magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair, we would apply Newton's Second Law of Motion:
First of all, we would calculate the total mass of the cat/elevator pair.
Total mass = 99 kilograms
Mathematically, Newton's Second Law of Motion is given by this formula;
Substituting the given parameters into the formula, we have;
Net force = 198 Newton
Read more here: brainly.com/question/24029674