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nadezda [96]
3 years ago
12

An ideal spring obeys hooke's law: f = −bikx. a mass of m = 0.3 kg hung vertically from this spring stretches the spring 0.13 m.

the acceleration of gravity is 9.8 m/s 2 . calculate the value of the force constant k for the spring. answer in units of n/m
Physics
1 answer:
Anarel [89]3 years ago
5 0
The force = 0.3 * 9.8 = 2.94
x = 0.13

k = 2.94/0.13
k = 22.6 N/m
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Answer:

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Explanation:

<u>Net Force </u>

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jekas [21]

The question is incomplete, the concentration of qam and humulin is not given unless R is used concentration

Complete question:

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