Question

An ideal spring obeys hooke's law: f = −bikx. a mass of m = 0.3 kg hung vertically from this spring stretches the spring 0.13 m. the acceleration of gravity is 9.8 m/s 2 . calculate the value of the force constant k for the spring. answer in units of n/m

Answer 1

The force = 0.3 * 9.8 = 2.94
x = 0.13

k = 2.94/0.13
k = 22.6 N/m