All categories

4 years ago

HELP ;

Physics

2 answers:

mestny [16]4 years ago

7 0

Answer:

The frequency would double.

Explanation:

Given:

Speed of wave (v) = constant.

Frequency of wave initially (f₁) = 2 Hz

Initial wavelength of the wave (λ₁) = 1 m

Final wavelength of the wave (λ₂) = 0.5 m

Final frequency of the wave (f₂) = ?

We know that the product of wavelength and frequency of the wave is equal to the speed of the wave.

Therefore, framing in equation form, we have:

Wavelength × Frequency = Speed

$\lambda\times f=v$

It is given that speed of the wave remains the same. So, the product must always be a constant.

Therefore,

$\lambda\times f=constant\ or\ \\\lambda_1\times f_1=\lambda_2\times f_2$

Now, plug in the given values and solve for 'f₂'. This gives,

$1\times 2=0.5\times f_2\\\\f_2=\frac{2}{0.5}=4\ Hz$

Therefore, the final frequency is 4 Hz which is double of the initial frequency.

f₂ = 2f₁ = 2 × 2 = 4 Hz

So, the second option is correct.

Veronika [31]4 years ago

7 0

Answer:

The answer is C The frequency would double.

Explanation:

You might be interested in

For small amplitudes of oscillation the motion of a pendulum is simple harmonic. Consider a pendulum with a period of 0.550 s Fi

Ivenika [448]

To solve this problem we will use the concepts related to the expression of energy for harmonic oscillator. From our given values we have that the period is equivalent to

$T = 0.55s$

Therefore the frequency will be the inverse of the period and would be given as

$f= \frac{1}{T}$

$f = \frac{1}{0.55}$

$f = 1.82s^{-1}$

The ground state energy of the pendulum is,

$E = \frac{1}{2} hv$

$E = \frac{1}{2}(6.626*10^{-34}J\cdot s)(1.82s^{-1})$

$E = 6.03*10^{-34}J$

The ground state energy in eV,

$E = 6.03 * 10^{-34}J(\frac{1eV}{1.6*10^{-19}J})$

$E = 3.8*10^{-15}eV$

The energy difference between adjacent energy levels,

$\Delta E = hv$

$\Delta E = (6.626*10^{-34}J\cdot s)(1.82s)$

$\Delta E = 12.1*10^{-34}J$

4 0

3 years ago

Block M = 7.50 kg is initially moving up the incline and is increasing speed with a = [09]____________________ m/s2 . The applie

Aliun [14]

Answer:

a) 73.2N

b) 66.6N

c) 20.28N

Explanation:

F= mg=7.5×9.8=73.5N

Force parallel to the plane Fp= 73.5sin25= 31.06N

b) Fv= 73.5 cos25= 66.6N

c) Ff= u×Fv= 0.312×66.6=20.28N

a) Normal ForceFn= F/(cos25) - Fp - Ff = ma

1.1F -31.06-20.28=7.5×3.82

1.1F -51.84=28.65

1.1F= 28.65+51.84

F= 80.49/1.1

F= 73.2N

4 0

3 years ago

A pulley has a mechanical advantage of 1.

sertanlavr [38]

Answer:

There is no mechanical advantage

Explanation:

The mechanical advantage is possible only when the force needed to lift a load is lesser than the weight of the load.

For example, is we have a mechanical advantage of 2, the force needed to lift will be 1/2 of the weight of the load, and if we have a mechanical advantage of 4, the force needed will be 1/4 of the weight of the load.

In the attached image there are clear examples of mechanical advantage with pulleys.

7 0

3 years ago

A battery is connected to the two ends of a conducting rod and the current through it is measured.a) Another rod, made of the sa

IceJOKER [234]

Answer:

a) - the resistance is proportional to the length of the metal

- a thicker rod, since resistance decreases with increasing area

b) The current is proportional to the area so this is the factor that is influenced by the electric field

Explanation:

a) When the rod is connected to the rod an electrical circuit described by the expression is formed

V = I R

I = V / R

The resistance of the rod is

R = ρ L / A

Where ρ is the resistivity of metal, L Longitud and A cross section.

If a higher current is measured when the other rod is connected, it implies that the resistance has decreased. To have a decrease in resistance you have two possibilities

- use a shorter rod, since the resistance is proportional to the length of the metal

- Use a thicker rod, since resistance decreases with increasing area, remember that the area of a circle is

A = π R²

Therefore, small increases in the diameter of the rod could give great changes in resistance.

b) The current is defined with the charge that crosses a surface per unit of time, when the electric field increases the electrons feel a greater force, therefore the current increases.

The charge number on a wire is

Q = q n $v_{d}$ Δt A

So up to date is

I = q n When the rod is connected to the rod an electrical circuit described by the expression is formed

V = I R

I = V / R

The resistance of the rod is

R = rho L / A

Where rho is the resistivity of metal, L e; Long and A cross section.

If a higher current is measured when the other rod is connected, it implies that the resistance has decreased. To have a decrease in resistance you have two possibilities

.- use a shorter rod, since the resistance is proportional to the length of the metal

. - Use a thicker rod, since resistance decreases with increasing area, remember that the area of a circle is

A = pi R2

Therefore, small increases in the diameter of the rod could give great changes in resistance.

.b) The current is defined with the charge that crosses a surface per unit of time, when the electric field increases the electrons feel a greater force, therefore the current increases.

The load number on a wire is

Q = q n $v_{d}$ Dt A

So current is

I = q n v_{d} A

The drag speed (v_{d}) is constant in the materials, it depends on the purity and imperfections, so a change in the length does not significantly change the current.

The current is proportional to the area so this is the factor that is influenced by the electric field

The drag speed (vd) is constant in the materials, it depends on the purity and imperfections, so a change in the length does not significantly change the current.

The current is proportional to the area so this is the factor that is influenced by the electric field

8 0

3 years ago

Name three common minerals in silicates

rjkz [21]

Quartz, feldspa, mica, amphibole, pyroxene and olivine

3 0

3 years ago