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Arisa [49]
3 years ago
5

How is gravity "best" described?

Physics
2 answers:
hram777 [196]3 years ago
8 0

Answer:

a fundamental force

Explanation:

Gravity is the only fundamental force that physicists can currently describe without using force-carrying particles.

Allisa [31]3 years ago
4 0

Answer:

Gravity is best described as a fundamental force.

Explanation:

Gravity is one of the 4 fundamental forces(3 of the forces out of 6).  

The description of mass is independent to Gravity. Since an objects mass determines the strength of the pull of Gravity. But it is not Gravity itself.

Molecular pull is more of a density determination. For example the pull between the atomic particles of a solid is stronger than those of a gas.

Thrust is a kind of acceleration. It is the push and resist to the drag force.

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A 1.5 kg ball has a velocity of 12 m/s just before it strikes the floor. Find the impulse on the ball if the ball bounces up wit
Andru [333]

Hi there!

Recall:

Impulse = Change in momentum

I = Δp = mΔv = m(vf - vi)

Let the direction TOWARDS the floor be POSITIVE, and AWAY be NEGATIVE.

Plug in the givan values:

Δp = 1.5(-10 - 12) = -33 Ns

**OR, the magnitude: |-33| = 33 Ns

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High pitched sounds have relatively large ___ and small ___
Mashutka [201]
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4 years ago
A 3-ton Toyota land cruiser travelled at a speed of 45m/s, collides with a 2- ton comfort taxi which was parked in front of the
Olin [163]

Answer:

v = 27 m/s

Explanation:

To find the speed of cars after the collision  you take into account the momentum conservation law. Total momentum of both cars before the collision must be equal to the total momentum of both cars after the collision.

After the collision both cars traveled together, then you have:

m_1v_1+m_2v_2=(m_1+m_2)v   (1)

m1: mass of the Toyota = 3-ton = 3000 kg

m2: mass of the taxi = 2-ton = 2000kg

v1: speed of the Toyota before the collision = 45m/s

v2: speed of the car before the collision = 0 m/s (it is  at rest)

v: speed of both cars after the collision = ?

You solve the equation (1) for v:

v=\frac{m_1v_1+m_2v_2}{m_1+m_2}

Next, you replace the values of the rest of the variables:

v=\frac{(3000kg)(45m/s)+0kgm/s}{3000kg+2000kg}=27\frac{m}{s}

hence, just after the collision both cars have a speed of 27m/s

7 0
3 years ago
Identify one similarity between between fission and fusion processes.
Lera25 [3.4K]

Answer:

C

Explanation:

because it is and it doesn't have to be in the indirect dialog

4 0
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What are the two forces acting on the upper magnet?
solniwko [45]

Answer:

b

Explanation:

I'm not so sure but it makes sense

8 0
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