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Hitman42 [59]
3 years ago
10

F(x)= 10x-5What is the value of f-1(-4) ?​

Physics
2 answers:
Afina-wow [57]3 years ago
6 0

Answer:

f^{-1}(-4) = \frac{1}{10}

Explanation:

Firstly finding f^{-1}(x)

So,

f(x) = 10x-5

Substitute y = f(x)

y = 10x-5

Exchange the values of x and y

x = 10y-5

Solving for y

x = 10y-5

Adding 5 to both sides

10y = x+5

Dividing both sides by 10

y = \frac{x+5}{10}

Replace y = f^{-1}(x)

f^{-1}(x) = \frac{x+5}{10}

For x = -4

f^{-1}(-4) = \frac{-4+5}{10}

f^{-1}(-4) = \frac{1}{10}

Eva8 [605]3 years ago
4 0

Answer:

\frac{1}{10}

Explanation:

f(x) = y (output)

y = 10x - 5

Switch variables.

Solve for y.

x = 10y - 5

x + 5 = 10y

x/10 + 1/2 = y

f^{-1}(x) = 1/10x + 1/2

Put x as -4.

1/10(-4) + 1/2

-4/10 + 1/2

-4/10 + 5/10

= 1/10

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