The element aluminum forms a cation with the charge of +3. The symbol for this ion is Al³⁺, and the name is aluminum ion. The number of electrons in this ion 10.
<h3>What are ions?</h3>
Ions are formed when an atom gains or loses electrons.
Metals form positive ions by a loss of electrons whereas non-metals form negative ions by gaining electrons.
The aluminum ion is formed when aluminum loses three electrons to form Al³⁺ ion which has 10 electrons.
in conclusion, ions are formed by a gain or loss of electrons.
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Answer:
75.15 mol.
Explanation:
- Firstly, we need to write the balanced equation of the reaction:
<em>Fe₂O₃ + 3CO → 2Fe + 3CO₂.</em>
It is clear that 1.0 mole of Fe₂O₃ reacts with 3.0 moles of CO to produce 2.0 moles of Fe and 3.0 moles of CO₂.
∴ Fe₂O₃ reacts with CO with (1: 3) molar ratio.
- we need to calculate the no. of moles of (4000 g) of Fe₂O₃:
<em>no. of moles of Fe₂O₃ = mass/molar mass</em> = (4000 g)/(159.69 g/mol) = <em>25.05 mol.</em>
<u>Using cross multiplication:</u>
1.0 mole of Fe₂O₃ needs → 3.0 moles of CO,
∴ 25.05 mole of Fe₂O₃ needs → ??? moles of CO.
<em>∴ The no. of moles of CO needed</em> = (3.0 mol)(25.05 mol)/(1.0 mol) =<em> 75.15 mol.</em>
Answer:
<h3>CH3OH (Methanol)</h3>
MM = 12 + 8 + 16 = 36u
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From the stoichiometry of the reaction, 1.4 * 10^-3 g is produced.
<h3>What mass of water is produced?</h3>
The equation of the reaction is written as; CO2 + 2LiOH → Li2CO3 + H2O. This can help us to apply the principle of stoichiometry here.
Thus;
Number of moles of CO2 = 0.00345 g/44 g/mol = 7.8 * 10^-5 moles
If 1 mole of CO2 produced 1 mole of water
7.8 * 10^-5 moles of CO2 produced 7.8 * 10^-5 moles of water
Mass of water produced = 7.8 * 10^-5 moles * 18 g/mol = 1.4 * 10^-3 g
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