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Over [174]
3 years ago
9

Th answer is "electric attraction is a force that can act at a distance."

Physics
1 answer:
Tasya [4]3 years ago
7 0
Electric forces is not action-by-distance. Charged particle emits a electric field radially outwards. It corresponds by the inverse-square, meaning it is 1/r^2.
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A solar panel is used to collect energy from the sun and change it into other forms of energy. The picture below shows some sola
irakobra [83]
C I’m pretty sure!!!!!
4 0
3 years ago
A ball of mass 0.120 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.820 m. W
Vikentia [17]

Answer:

1.0752 kgm/s

Explanation:

Considering when the drop was dropped from rest from a height,

mass of the ball, m = 0.120 kg

height, h = - 1.25 m

the initial velocity, u = 0 m/s

the acceleration due to gravity, g = - 9.8 m/s²

From equation of motion

                            V^{2} = U^{2} + 2gh

Substituting the values,

                             V^{2} = 0^{2} + 2(-9.8 m/s^{2})(-1.25 m)

                             V^{2} = 24.5 m/s

                             V = \sqrt{24.5} \ m/s

                             V = 4.95 \ m/s

                            V = ± 4.95 m/s

                            V = - 4.95 m/s

Since the ball is moving downward, the final velocity of the ball when it hits the floor is  V = - 4.95 m/s  

Considering when the ball rebounds from the floor,

assume the mass of the ball still remain, m = 0.120 kg

height, h = 0.820 m

the final velocity, v = 0 m/s  

the acceleration due to gravity, g = - 9.8 m/s²

From equation of motion

                            V^{2} = U^{2} + 2gh

Substituting the values,

                            0^{2} = U^{2} + 2(-9.8 m/s^{2})(0.820 m)

                            0 = U^{2} - 16.072 m/s

                            U^{2} = 16.072 m/s

                            U = \sqrt{16.072} \ m/s

                           U = ± 4.01 m/s

                          U = + 4.01 m/s

Since the ball is moving upward, the initial velocity of the ball from the bounce from the floor is  U = + 4.01 m/s                        

From Newton's second law of motion, applied force is directly proportional to the rate of change in momentum.

                            F = \frac{mv - mu}{t}

                          F.t = m(v - u)

       ⇒      Impulse = Change in momentum

To calculate the impulse, the moment before the ball hits the ground will be the initial momentum while the moment the ball rebounces will be the final velocity,                        

          ∴          F.t = 0.120  kg(4.01  m/s - (-4.95  m/s) )

                      F.t = 0.120  kg(4.01  m/s + 4.95  m/s) )

                      F.t = 0.120  kg × 8.96  m/s

                      Impulse  = 1.0752 kgm/s

The impulse given to the ball by the floor is 1.0752 kgm/s

                             

6 0
3 years ago
A mineral's chemical composition and crystal structure help determine it's ___________.
AnnyKZ [126]

Hiya!

The answer to your question is B.

Physical Properties.

~Hope this helps~

4 0
3 years ago
Does 3.60 x 10 ⁻² have 2 significant figures
Mandarinka [93]

Answer:

Number of Significant Figures: 2

The Significant Figures are 3 6

Explanation:

= 3.60 × 102

(scientific notation)

= 3.60e2

(scientific e notation)

= 360 × 100

(engineering notation)

(one)

= 360

(real number)

4 0
3 years ago
According to Newton's third law, two objects interacting under a force (such as gravity) both feel the same force. If the planet
asambeis [7]

Explanation:

That's because the Sun's acceleration is much smaller

8 0
2 years ago
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