Answer:
Explanation:
The total energy of the satellite when it is still in orbit is given by the formula
where
G is the gravitational constant
m = 525 kg is the mass of the satellite
is the Earth's mass
r is the distance of the satellite from the Earth's center, so it is the sum of the Earth's radius and the altitude of the satellite:
So the initial total energy is
When the satellite hits the ground, it is now on Earth's surface, so
so its gravitational potential energy is
And since it hits the ground with speed
it also has kinetic energy:
So the total energy when the satellite hits the ground is
So the energy transformed into internal energy due to air friction is the difference between the total initial energy and the total final energy of the satellite:
The frequency of oscillation is 2.153 Hz
What is the frequency of spring?
Spring Frequency is the natural frequency of spring with a weight at the lower end. Spring is fixed from the upper end and the lower end is free.
For the mass-spring system in this problem,
The Frequency of spring is calculated with the equation:
Where,
f = frequency of spring
k = spring constant = 64 N/m
m = mass attached to spring = 350g = 0.350 kg
a = maximum acceleration = 5.3 m/s^2
Substituting the values in the equation,
Hence,
The frequency of oscillation is 2.153 Hz
Learn more about frequency here:
<u>brainly.com/question/13978015</u>
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<span>The minimum amount of energy that has to be added to start a reaction is the activation energy.</span>
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