Q = mc∆t, where:
q = energy flow
m = mass, 120 000 g
c = specific heat capacity, 4.81 J/gC
∆t = change in temperature, ~75 (100 - 25, which is room temperature)

Substituting in the values, we get:
q = 120000 x 4.81 x 75 = 43290000 Joules = 43.29 MJ

Hope I helped!! xx

7 0

2 years ago

Find expressions for the force needed to bring an object of mass m from rest to speed v in time t. express your answer in terms

VARVARA [1.3K]

Good morning.

We have that:

$\mathsf{V = a\cdot t}$ , since we have rest in the inicial time.

The acceleration can be found with Newton's Law:

$\mathsf{F = m\cdot a\iff a = \dfrac{F}{m}}$

Now we put the acceleratin in the velocity equation:

$\mathsf{V = \dfrac{F}{m} \cdot t}$

We want the force, so, let's isolate F:

$\mathsf{V\cdot m = F\cdot t}\\ \\ \\ \boxed{\mathsf{F = \dfrac{V\cdot m}{t}}}$

3 0

2 years ago

Hammer falls off a roof top and strikes the ground with a certain kinetic energy. If it fell

Galina-37 [17]

Answer:

If the starting GPE is doubled than it's KE would also double.

6 0

3 years ago