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2 years ago

From the anatomical position, the digits are ____ to the brachium.

Physics

2 answers:

dedylja [7]2 years ago

7 0

I think is a if I’m wrong tell em I’ll re slove this

PIT_PIT [208]2 years ago

4 0

A I believe if not I’m sorry

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Two stars have the same radius but have very different temperatures. the red star has a surface temperature of 3,000 k and the b

dangina [55]

I would say that insofar as the two stars temperatures are presumably closely related to their luminosity, that the blue star at 156,100 k compared to 3000k for the red star then the blue star has a luminosity of 52 times that of the red star.

4 0

3 years ago

what are three activities in your everyday life that involve electromagnetic energy? and explain what type of electromagnetic en

mihalych1998 [28]

1). While I'm driving the car, I keep my eyes pointed out the front window,

so that LIGHT WAVES coming straight in through the front window get into

them. Using this process, I'm able to SEE what's in front of me, so that I don't

drive straight into it.

2). Also while I'm driving the car, I usually have the radio on, and I tune it

to a frequency where the RADIO WAVES that it responds to are being

modulated by people who are either talking or else playing classical music.

3). Before I leave the house on most days, I take a small container of

frozen Irish oatmeal out of the freezer, and I load it into the big box

above the stove, where MICROWAVE ENERGY thaws it, and warms

it to a nice eating temperature.

3A). When I arrive at my job, I usually do things that are also associated

in some way with MICROWAVE energy, since I work as a microwave

system design engineer. Most of the time it's just paperwork, but there

ARE times when I work with an actual radio that's either generating or

detecting real microwave energy, and either sending it up to, or receiving

it down from, a big dish antenna on a radio tower. Those are the days that

I like the best.

8 0

3 years ago

How are momentum and collision related?

Studentka2010 [4]

Answer:

im pretty sure a collision is a transfer of momentum.

Explanation:

hope this helps :)

5 0

3 years ago

A 1.50 kg rock is thrown up into the air from ground level, reaches a maximum height of 7.00 m, then returns to the ground. Calc

Minchanka [31]

Answer:

17.565 kgm/s

Explanation:

Momentum = mass × velocity

I = mv..................... Equation 1

But we can calculate the value of v using the equation of motion under gravity.

v² = u²+2gs............. Equation 2

Where u = initial velocity, s = maximum heigth, g = acceleration due to gravity.

Given: u = 0 m/s (at the maximum heigth), s = 7.0 m.

Constant: g = 9.8 m/s²

Substitute these values into equation 2

v² = 0²+ 2×7×9.8

v² = 137.2

v = √137.2

v = 11.71 m/s.

Also given: m = 1.50 kg

substitute these values into equation 1

Therefore,

I = 1.5×11.71

I = 17.565 kgm/s

3 0

2 years ago

A space vehicle is traveling at 5425 km/h relative to the Earth when the exhausted rocket motor (mass 4m) is disengaged and sent

lana66690 [7]

Answer:

$V_{cE}=1489m/s$

Explanation:

Given data

Space vehicle speed=5425 km/h relative to earth

The rocket motor speed=81 km/h and mass 4m

The command has mass m

From the conservation of momentum as the system isolated

$p_{i}=p_{f}\\$

Since the motion in on direction we can drop the unit vector direction

$MV_{i}=4mV_{mE}+mV_{CE}$

Where M is the mass of space vehicle which equals to sum of the motors mass and command mass.

The velocity of the motor relative to the earth equals the velocity of the motor relative to command plus the velocity of the command relative to earth

$V_{mE}=V_{mc}+V_{cE}$

Where Vmc is the velocity of motor relative to command

This yields

$5mV_{i}=4m(V_{mc}+V_{cE})+mV_{cE}\\5V_{i}=4V_{mc}+5V_{cE}$

Substitute the given values

$V_{cE}=\frac{5V_{i}-4V_{mc}}{5}\\ V_{cE}=5425*\frac{1000}{60*60}(m/s)-\frac{4}{5}*81\frac{1000}{60*60}(m/s)\\ V_{cE}=1489m/s$

5 0

3 years ago