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Katena32 [7]
4 years ago
8

A student analyzed an antacid tablet from a bottle containing 120 tablets purchased for $2.79. The mass of the tablet was 1.247

grams. What is the cost of one antacid tablet in cents/tablet?
Chemistry
1 answer:
BaLLatris [955]4 years ago
5 0

The cost of one antacid is 2.325 cents per tablet.

<u>Explanation:</u>

As per the question based on the student analysis we know that,

Total antacid tablets in a bottle = 120

Purchase Price of a bottle = $ 2.79

Cost of 1 antacid tablet =\frac{2.79}{120}  

As we know $1 = 100 cent

The cost of 1 antacid tablet = \frac{2.79}{120} × 100 cents = 2.325 cents/tablet .

Thus we came to know that it costs 2.325 cents/tablet .

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<span>A carbon - 12 atom and a regular carbon atom would have the same number of protons which is 6. So a carbon - 12 atom would have 6 protons. Both, however, would differ in the number of neutrons. Carbon - 12 atom has 6 neutrons. To determine the mass defect of a carbon - 12 atom, we have to add the total mass of protons and the total mass of neutrons and subtract the known mass of a carbon - 12 atom. That would be like this.<span>
6 (1.00728 amu) + 6 (1.00866 amu) = x
<span>6.04368 amu<span> + 6.05196 amu = x</span></span>
12.09564 amu = x

Then subtract it with 12 amu to get the defect mass

12.09564 amu - 12.00000 amu = y
0.09564 amu = y

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6 0
3 years ago
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Consider 55 mL of water (H2O) in a beaker and 55 mL of acetone |(CHs)2CO in an identical beaker under identical conditions Compl
Zepler [3.9K]

Answer:

1. more slowly than

2. larger than

3. weaker

Explanation:

Acetone molecules are bonded by very weak intermolecular forces when compared to that of the hydrogen bond between water molecules. This makes it very easy for acetone molecules to vaporize easily into its gaseous state, much more faster than water molecules (since the acetone molecules need a lesser amount of energy to break these bonds). Also, the boiling point of liquid acetone is much lower than that of water, meaning that it has a higher vapor pressure than that of water.

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3 years ago
Sulfur is right below oxygen in the periodic table, meaning it has similar bonding properties. Like oxygen, sulfur can form a co
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Sulfur’s Bohr diagram 1 S^2 2S^2 2P^6 3S^2 3S^4. Like Oxygen, needs 2 electrons on outer ring to become stable.

3 0
3 years ago
How much CO2 is produced from the combustion of a tank of propane C3H8? Assume the tank contains 9kgs of propane and the molecul
Zinaida [17]

<u>Answer:</u> The mass of carbon dioxide produced is 26.9 kg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of propane = 9 kg = 9000 g    (Conversion factor:  1 kg = 1000 g)

Molar mass of propane = 44.1 g/mol

Putting values in equation 1, we get:

\text{Moles of propane}=\frac{9000g}{44.1g/mol}=204.08mol

The chemical equation for the combustion of propane follows:

C_3H_8+5O_2\rightarrow 3CO2+4H_2O

By Stoichiometry of the reaction:

1 mole of propane produces 3 moles of carbon dioxide.

So, 204.08 moles of propane will produce = \frac{3}{1}\times 204.08=612.24mol of carbon dioxide.

Now, calculating the mass of carbon dioxide by using equation 1, we get:

Molar mass of carbon dioxide = 44.01 g/mol

Moles of carbon dioxide = 612.24 moles

Putting values in equation 1, we get:

612.24mol=\frac{\text{Mass of carbon dioxide}}{44.01g/mol}\\\\\text{Mass of carbon dioxide}=(612.24mol\times 44.01g/mol)=26944.7g=26.9kg

Hence, the mass of carbon dioxide produced is 26.9 kg

3 0
3 years ago
According to the following reaction, how many moles of calcium chloride will be formed upon the complete reaction of 27.9 grams
I am Lyosha [343]

Answer: 0.377 moles of calcium chloride will be formed.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

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The balanced chemical reaction is:

Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O  

According to stoichiometry :  

As 1 mole of Ca(OH)_2 give = 1 mole of CaCl_2

Thus 0.377 moles of Ca(OH)_2 give =\frac{1}{1}\times 0.377=0.377moles  of CaCl_2  

Thus 0.377 moles of calcium chloride will be formed upon the complete reaction of 27.9 grams of calcium hydroxide with excess hydrochloric acid

3 0
3 years ago
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