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lapo4ka [179]
2 years ago
10

A sample of gas is collected in a flask with a volume of 267 mL at a pressure of 771 mmHg and a temperature of 21C. If the mass

of the gas is 1.05 g, what is the molar mass of the gas?
Chemistry
1 answer:
nadya68 [22]2 years ago
6 0

Answer:

M=93.5g/mol

Explanation:

I did this in class and it was a review. :)

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Gold has a very high density of about 19.32g/cm^3 while Aluminum has a low density of 2.7 gm/cm^3 which means gold can pack more amount of matter in a comparatively small space as compared to Aluminum.
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1. A 50 gram sample of a radioisotope decays to 12.5 grams in 14.4 seconds. What is
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Half life = 7.2 seconds

Explanation:

from \: decay \: equation \\ 2.303 log( \frac{n.}{nt} )  = kt \\ 2.303 log( \frac{50}{12.5} )  = k \times 14.4 \\ k =  \frac{2.303 log( \frac{50}{12.5} )}{14.4}  \\ k = 0.096288 {s}^{ - 1}  \\ since \: half \: life =  \frac{ ln(2) }{k}  \\ half \: life  =   \frac{ ln(2) }{0.096288}  \\ half \: life = 7.2 \: seconds

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Which of these is a characteristic of a virus?
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Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl ( aq ) , as describe
Nataly [62]

Answer:

0.9483 grams of manganese dioxide should be added to excess HCl.

Explanation:

Pressure of the chlorine gas = P = 795 Torr = 1.046 atm  (1 atm = 760 Torr)

Volume of the chlorine gas = V = 255 ml = 0.255 L

Temperature of the chlorine  gas = T = 25°C= 298.15 K

Moles of chlorine gas = n

Using ideal gas equation:

PV = nRT

n=\frac{PV}{RT}=\frac{1.046 atm\times 0.255 L}{0.0821 atm l/mol k\times 298.15 K}

n = 0.01090 mol

MnO_2 ( s ) + 4 HCl ( aq)\rioghtarrow  MnCl_2 ( aq ) + 2 H_2O ( l ) + Cl_2 ( g )

According to reaction , 1 mole of chlorine gas is obtained from 1 mole of manganese dioxide.

Then 0.01090 moles of chlorine gas will be obtained from:

\frac{1}{1}\times 0.01090 mol=0.01090 mol manganese dioxide

Mass of 0.01090 moles of manganese dioxide:

0.01090 mol × 87 g/mol = 0.9483 g

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What type of element is chlorine?
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Halogen is the answer

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