Hello. This question is incomplete. The full question is:
"Consider the following reaction. 2NO(g) + 2H2(g) → N2(g) + 2H2O(g)
A proposed reaction mechanism is: NO(g) + NO(g) N2O2(g) fast N2O2(g) + H2(g) → N2O(g) + H2O(g) slow N2O(g) + H2(g) → N2(g) + H2O(g) fast
What is the rate expression? A. rate = k[H2] [NO]2 B. rate = k[N2O2] [H2] C. rate = k[NO]2 [H2]2 D. rate = k[NO]2 [N2O2]2 [H2]"
Answer:
A. rate = k[H2] [NO]2
Explanation:
A reaction mechanism is a term used to describe a set of phases that make up a chemical reaction. In these phases a detailed sequence of each step is shown, composed of several complementary reactions, which occur during a chemical reaction.
These mechanisms are directly related to chemical kinetics and allow changes in reaction rates to be observed in advance.
Reaction rate, on the other hand, refers to the speed at which chemical reactions occur.
Based on this, we can observe through the reaction mechanism shown in the question above, that the action "k [H2] [NO] 2" would have no changes in the reaction rate.
- <span>The </span>speed of light<span> is the </span>speed<span> electromagnetic waves travel. The </span>speed of light<span> is 3.0 x 108 m/s in space. The </span>speed of light<span> is the same in all matter. The </span>speed<span> of higher frequency </span>light <span>slows down more than lower frequency </span>light<span> in matter.</span>
Answer:
<u>Mass concentration (g/L) </u><u><em>= 2.49g/L.</em></u>
Explanation:
No. of moles = 
= 
= 0.001245 moles
Concentration of KHP (C1) in litres = n/v
= 
= 0.062 mol/L
We know that:
= 
where c1v1 and c2v2 are the products of concentration and volumes of KHP and NaOH respectively.
Since mole ratio is 1 : 1.
1 mole of NaOH - 40g
0.001245 mole of NaOH = 40 × 0.001245 = 0.0498g
⇒0.0498g of NaOH was used during the titration
<u><em>∴Mass concentration (g/L) = 0.0498g ÷ 0.02L</em></u>
<u><em>= 2.49g/L.</em></u>
Answer:
10 L of CO₂.
Explanation:
The balanced equation for the reaction is given below:
2CO + O₂ —> 2CO₂
From the balanced equation above,
2 L of CO reacted to produce 2 L of CO₂.
Finally, we shall determine the volume of CO₂ produced by the reaction of 10 L CO. This can be obtained as follow:
From the balanced equation above,
2 L of CO reacted to produce 2 L of CO₂.
Therefore, 10 L of CO will also react to produce 10 L of CO₂.
Thus, 10 L of CO₂ were obtained from the reaction.
Answer:
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Explanation:
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