Question

Joyce has a cone shaped planter hanging on her back porch. If the planter has a radius 6.8 inches and a height of 12.2 inches, what is the total amount of soil that the planter will hold to the nearest tenth

Answer 1

Answer:

The total amount of soils that planter will hold to it is 590.45  inches³

Step-by-step explanation:

Given as :

The radius of the cone shape planter = r = 6.8 inches

The height of the cone shape planter = h = 12.2 inches

Let The total amount of soils that will hold to it = x cubic inches

Now, According to question

The total amount of soils that planter will hold to it = The volume of the cone

∵ The volume of cone = v = $\dfrac{1}{3} \pi$ r² h

where r is the radius

And h is the height

So, The total amount of soils that planter will hold to it =  $\dfrac{1}{3} \pi$ r² h

or, x = $\dfrac{1}{3}$ × $\pi$ × r² × h

or, x =  $\dfrac{1}{3}$ × 3.14 × (6.8)² inches × 12.2 inches

or, x =  $\dfrac{1}{3}$ × 3.14 × 564.128 inches³

or, x =  $\dfrac{1}{3}$ × 1771.361  inches³

or, x = $\dfrac{1771.361}{3}$  inches³

∴  x = 590.45  inches³

So, The total amount of soils that planter will hold to it = x = 590.45  inches³

Hence, The total amount of soils that planter will hold to it is 590.45  inches³   . Answer