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2 years ago

Which buffer system is found in the human body?

Chemistry

1 answer:

aivan3 [116]2 years ago

8 0

The correct answer is the bicarbonate buffer system.

The bicarbonate buffer system refers to an acid-base homeostatic mechanism taking part in the balance of bicarbonate ion, carbonic acid, and carbon dioxide in order to sustain the pH in the duodenum and blood, among other tissues, to support the entire metabolic activities.

The bicarbonate buffer system plays a vital role in the human body systems. In the duodenum and the stomach, the bicarbonate buffer system functions to both neutralize gastric acid and steady the intracellular pH of epithelial cells through the secretion of bicarbonate ion into the gastric mucosa.

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In a sample containing a mixture of only these gases at exactly one atmosphere pressure, the partial pressures of carbon dioxide

Black_prince [1.1K]

Answer:

Explanation:

The pressure of a gaseous mixture is equal to the sum of the partial pressures of the individual gases:

Σ $P_g_a_s$ $= P_1+P_2+P_3+...+P_n$

The prompt is trying to confuse you, but it actually tells us the pressure of the mixture to be 1 atm, but this can be converted to torr. Furthermore, we are informed only three gases are in the mixture: diatomic nitrogen, diatomic oxygen, and carbon dioxide:

$P_g_a_s=1 \ atm = 760 \ torr= P_N_2+P_O_2+P_C_O_2\\760 \ torr = 582.008 \ torr + P_O_2 \ + 0.285 \ torr$

Solve for Po2:

$P_o_2=(760-582.008-0.285) \ torr = 177.707 \ torr$

Thus, the partial pressure of diatomic oxygen is 177.707 torr.

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4 0

2 years ago

Alecsey [184]

Answer:

<h3>no it is not allowed</h3>

Explanation:

<h3>Liwis structure shows the elements symbol with dots thet represents valance electrons ; in second row elements their atomic number is 3 up to 10 , from Li up to Ne from their electron configuration their valance electron will be from 1 up to 8 respectivelly ,if lewis structure represents the element with it is symbol and dots that represents valance electron the second row elements cannot have more than an octet of valance electrons surrounding it.</h3>

<h3>I think it is help ful for you </h3>

3 0

2 years ago

How many particles are in one mole substance

Karolina [17]

Avogadro's number is defined as the number of elementary particles (molecules, atoms, compounds, etc.) per mole of a substance. It is equal to 6.022×1023 mol-1 and is expressed as the symbol NA.

6 0

3 years ago

Read 2 more answers

a 25 ml volume of a sodium hydroxide solution requires 19.6 mL of a 0.189 M HCl acid for neutralization. A 10 mL volume of phosp

Drupady [299]

Answer: 0.172 M

Explanation:

a) To calculate theconcentration of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=0.189M\\V_1=19.6mL\\n_2=1\\M_2=?\\V_2=25mL$

Putting values in above equation, we get:

$1\times 0.189\times 19.6=1\times M_2\times 25\\\\M_2=0.148$

b) To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_3PO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?\\V_1=10mL\\n_2=1\\M_2=0.148\\V_2=34.9mL$

Putting values in above equation, we get:

$3\times M_1\times 10=1\times 0.148\times 34.9\\\\M_1=0.172M$

The concentration of the phosphoric acid solution is 1.172 M

3 0

3 years ago

A fuel tank holds 22.3 gallons of gasoline. If the density is 0.8206 g/mL, what is the mass in kilograms of gasoline in a full t

7nadin3 [17]

Answer:

$m=69.3kg$

Explanation:

Hello!

In this case, since the density is computed by dividing the mass of the substance by its occupied volume (d=m/V), we first need to realize that 0.8206 g/mL is the same to 0.8206 kg/L, which means we first need to compute the volume in L:

$V=22.3gal*\frac{3.78541L}{1gal}=84.415L$

Then, solving for the mass in d=m/V, we get m=d*V and therefore the mass of gasoline in that full tank turns out:

$m=0.8206g/L*84.415L\\\\m=69.3kg$

Best regards!

8 0

2 years ago