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Bess [88]
3 years ago
15

Which buffer system is found in the human body?

Chemistry
1 answer:
aivan3 [116]3 years ago
8 0

The correct answer is the bicarbonate buffer system.  

The bicarbonate buffer system refers to an acid-base homeostatic mechanism taking part in the balance of bicarbonate ion, carbonic acid, and carbon dioxide in order to sustain the pH in the duodenum and blood, among other tissues, to support the entire metabolic activities.  

The bicarbonate buffer system plays a vital role in the human body systems. In the duodenum and the stomach, the bicarbonate buffer system functions to both neutralize gastric acid and steady the intracellular pH of epithelial cells through the secretion of bicarbonate ion into the gastric mucosa.  


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Draw a resonance structure for the cyclopentadienyl anion. Be sure to show all non-bonding electrons and charges explicitly.
Gennadij [26K]

Answer:

The resonance structure for the cyclopentadienyl anion is shown in the drawing below.

Explanation:

The resonance representation of the cyclopentadienyl anion shows that it is a stable ion. On the other hand it is important to note that it has 6 π electrons and is aromatic.

4 0
3 years ago
If a piece of matter changes shape, how does its mass change?
kap26 [50]

The law of conservation of mass states that matter cannot be created nor destroyed the answer would be D. It remains the same
5 0
3 years ago
Which is the correct electron configuration for sodium?
sattari [20]

Explanation:

Ne] 3s¹ is the answer your welcome

7 0
2 years ago
Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:
Setler [38]

The order of frequency is d < a < c < b

E_{n} = 13.6 * z^{2} / n^{2} eV

where z = atomic mass number

n = energy level

For hydrogen z = 1

Therefore, Energy for n = 1

E_{n} = 13.6 * 1^{2} / 1^{2} eV

     = -13.6 eV

for n = 2

E_{n} = 13.6 * 1^{2} / 2^{2} eV

     = -3.40 eV

for n = 3

 E_{n} = 13.6 * 1^{2} / 3^{2} eV

      = -1.51 eV

for n = 4

 E_{n} = 13.6 * 1^{2} / 4^{2} eV

      = -0.85 eV

for n = 5

 E_{n} = 13.6 * 1^{2} / 5^{2} eV

      = -0.544 eV

n = 2 to n = 4 (absorption)

ΔE = E4 - E2   = -0.85 - (-3.40) = 2.55 eV

n = 2 to n = 1 (emission)

ΔE =  E1 - E2  = -13.6 - (-3.40) = -10.2eV

The negative sign indicates that emission will take place.

n = 2 to n = 5 (absorption)

ΔE = E5 - E2 = -0.544 - (-3.40) = 2.856 eV

n = 4 to n = 3 (emission)

ΔE = E3 - E4 = -1.51 - (-0.85) = -0.66 eV

We know that

E = h * υ

Therefore, Energy is proportional to frequency.

So increasing the order of energy is

E4  < E1  < E3  <  E2

order of frequency is

d < a < c < b

For more information click on the link below:

brainly.com/question/17058029

# SPJ4

8 0
1 year ago
Which reaction creates more massive nuclei?
maxonik [38]

Answer:

C. fusion

hope this helps

6 0
3 years ago
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