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3 years ago

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Which of the following characteristics is not a property of an acid? Has a sour taste Accepts an H+ ion in reaction May cause da

mage to buildings, statues, and rivers Increases the concentration of hydronium ions in an aqueous solution

2 answers:

9966 [12]3 years ago

5 0

Answer : The incorrect option is, Accepts an H⁺ ion in reaction.

Explanation :

Acid : It is a type of species which contains hydrogen ion.

Properties of an acid :

The taste of an acid is sour.

An acid does not feel slippery.

Acid reacts with the active metal to form a gas and a salt.

It change the color of litmus paper to red or pink.

It conduct electricity.

It react with carbonates to give salt.

It react with a metal to give compound and hydrogen gas.

Base : It is a type of species which contains hydroxide ion.

Properties of an base :

The taste of base is bitter.

The base feels slippery.

It does not react with the active metal.

It change the color of litmus paper to blue.

It conduct electricity.

As per question, all options are the properties of an acid while the statement accepts an H⁺ ion in reaction is in the property of an acid because it donates hydrogen ion in the solution.

Hence, the incorrect option is, Accepts an H⁺ ion in reaction.

tankabanditka [31]3 years ago

4 0

Answer : Option B) Accepts an H+ ion in reaction

Explanation : Acid is a lewis acid which forms a bond by accepting a pair of electrons. Acids, when dissolved increase the concentration of hydronium ion in the solution. So, the statement which is Acid accepts H+ ion is irrelevant here, as base accepts the H+ ion in a reaction.

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Be sure to answer all parts. What is the [H3O+] and the pH of a buffer that consists of 0.26 M HNO2 and 0.89 M KNO2? (K, of HNO2

Aleksandr-060686 [28]

Answer : The $H_3O^+$ ion concentration is, $1.12\times 10^{-3}M$ and the pH of a buffer is, 2.95

Explanation : Given,

$K_a=7.1\times 10^{-4}$

Concentration of $HNO_2$ (weak acid)= 0.26 M

Concentration of $KNO_2$ (conjugate base or salt)= 0.89 M

First we have to calculate the value of $pK_a$ .

The expression used for the calculation of $pK_a$ is,

$pK_a=-\log (K_a)$

Now put the value of $K_a$ in this expression, we get:

$pK_a=-\log (7.1\times 10^{-4})$

$pK_a=4-\log (7.1)$

$pK_a=3.15$

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

$pH=pK_a+\log \frac{[KNO_2]}{[HNO_2]}$

Now put all the given values in this expression, we get:

$pH=3.15+\log (\frac{0.89}{0.26})$

$pH=2.95$

The pH of a buffer is, 2.95

Now we have to calculate the $H_3O^+$ ion concentration.

$pH=-\log [H_3O^+]$

$2.95=-\log [H_3O^+]$

$[H_3O^+]=1.12\times 10^{-3}M$

The $H_3O^+$ ion concentration is, $1.12\times 10^{-3}M$

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3 years ago

When people walked on the Moon, they found that they could jump higher than they could back on Earth. Why is this true?

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Answer: B

Explanation: the moon is smaller and contains less mass, therefore its gravitational pull is less than that of Earth's.

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3 years ago

In an experiment, marble chips reacted with dilute hydrochloric acid and carbon dioxide gas was given

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Answer:

no

Explanation:

Small marble chips reacts faster

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3 years ago

determine the freezing point depression of a solution that contains 30.7 g glycerin (c3h8o3, molar mass

Blababa [14]

The freezing point depression of a solution containing 30.7 g of glycerin is calculated as -1.65°C

Equating :

It is given that,

Given mass of glycerin is = 30.7 grams (Solute)

Volume of water = 376 mL

$K_{f}$ or molar -freezing-depression point is = 1.86°C/m

Molar mass of glycerin = 92.09 g/mole

Now, to work out the value, the mass of water should be known. Thus, to calculate, the formula used will be:

Mass = Density X Volume

Mass = 1.0 g/mL X 376 mL

Mass = 376 g or 0.376 Kg

Using the formula of melting point depression, the equation becomes:

Δ $T_{f}$ = i × $K_{f}$ ×m

T⁰- $T_{s}$ = $i *K_{f} *\frac{mass of glycerin}{molar mass of glycerin * mass of water in kg}$

in which,

Δ $T_{f}$ = change in freezing point

Δ $T_{s}$ = freezing point of solution that has to be find

ΔT° = freezing point of water ()

Since, glycerin is a non-electrolyte, the Van't Hoff factor will be 1.

Substituting the values in the above equation:

0⁰C₋T $_{s}$ = 1 ×1.86°C/m × $\frac{30.7}{92.09g/mol * 0.376kg}$

$T_{s}$ = -1.65°C

Thus, the freezing point depression of a solution is -1.65°C

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Freezing point depression

Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all less than that of the pure solvent and is directly proportional to the molality of the solute

Is melting point elevation or depression?

Boiling point elevation is that the raising of a solvent's boiling point due to the addition of a solute. Similarly, melting point depression is the lowering of a solvent's freezing point due to the addition of a solute. In fact, because the boiling point of a solvent increases, its melting point decreases

Learn more about freezing point depression :

brainly.com/question/26525184

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1 year ago

Describe how elements are laid out on the periodic table of elements.

defon

Answer:

The chemical elements are arranged in order of increasing atomic number.

Explanation:

Hydrogen = 1

Helium = 2

Lithium = 3

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