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Stells [14]
3 years ago
11

In order to be considered work, the components that must be present are?..

Physics
2 answers:
AVprozaik [17]3 years ago
5 0
I think the answer is A.
mr_godi [17]3 years ago
4 0

If you need to be sure about this answer don't be I just took the test and this one was correct.

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The container was lifted a height of 14 m
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Force = 3 430 000J / 14m
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What is Intracellular communication
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Which scientist’s law about the ratios of masses of elements in a compound did john dalton’s work on the atomic structure help t
yanalaym [24]

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SF

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3 years ago
A weight is hung from the ceiling of an elevator by a massless string. Under which circumstances will the tension in the cord be
Oduvanchick [21]
When the elevator is going up (assuming the elevator is acceleration)

When the elevator is accelerating downwards, the total gravitational force would be larger.

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4 0
3 years ago
When a low-pressure gas of hydrogen atoms is placed in a tube and a large voltage is applied to the end of the tube, the alors w
Triss [41]

Answer:

A)  λ = 4.88 10² nm,  B)   λ = 4.08 10² nm

Explanation:

The spectrum of hydrogen is correctly explained by the Bohr model, where the energy of each level is

          Eₙ = -13.606 /n²       [eV]

the transition generally occurs from a given level to a lower state nf <no, so a transition is

          ΔE = E_f -Eₙ = -13,606 ( \frac{1}{n_f^2} - \frac{1}{n_o^2} )

to find the wavelength let's use the planck relation

          ΔE = h f

the speed of light is

          c = λ f

we substitute

          ΔE = h c /λ

          λ = \frac{h \ c}{ \Delta \lambda}

       

let's apply this equation to our case

the Balmer series has as final state the level n_f = 2

A) initial state n₀ = 4, final state n_f = 2

         ΔE = -13.606 ( \frac{1}{2^2} - \frac{1}{4^2} )

         ΔE = 2.55 eV

let's reduce to SI units

         ΔE = 2.55 eV (1.6 10⁻¹⁹ J / 1 eV) = 4.08 10⁻¹⁹ J

     

we calculate

         λ = 6.63 10⁻³⁴ 3 10⁸ / 4.08 10⁻¹⁹

         λ = 4.875 10⁻⁻⁷ m

we reduce to nm

         λ = 4.875 10⁻⁷ m (10⁹ nm / 1m)

         λ = 487.5 nm

we reduce to three significant figures

         λ = 4.88 10² nm

B) initial state n₀ = 5

          ΔE = -13,606 ( \frac{1}{2^2}  - \frac{1}{5^2} )

          ΔE = 2,857 eV

we repeat the process of the previous point

         ΔE= 2,857 1.6 10⁺¹⁹ = 4.286 10⁻¹⁹J

we look for the wavelength

           λ = 6.63 10⁻³⁴ 3 10⁸ / 4.88 10⁻¹⁹

           λ = 4.0758 10⁻⁷ m

we reduce to nm

           λ = 4.0758 10² nm

ignificant numbers

           λ = 4.08 10² nm

4 0
3 years ago
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