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Stells [14]
3 years ago
11

In order to be considered work, the components that must be present are?..

Physics
2 answers:
AVprozaik [17]3 years ago
5 0
I think the answer is A.
mr_godi [17]3 years ago
4 0

If you need to be sure about this answer don't be I just took the test and this one was correct.

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Waves transmit energy without transmitting matter, This means that we can move energy or information from one place to another without moving any substance from one place to another.
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Which of the following processes is not regarded as contributing to the creation of greenhouse gases? deforestation creating ele
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Creating electricity from wind is not regarded as a process contributing to the creation of greenhouse gases. Meanwhile, the processes such as deforestation, the creation of electricity from coal <span>and the use of fertilizers </span><span>are greatly contributing to the making of greenhouse gases.</span>

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A 1000 kg elevator accelerates upward at 1.0 m/s2 for 10 m, starting from rest. a. How much work does gravity do on the elevator
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Here you go mate. Hope it helps u. Pls follow me in reddit lol username: RobloxNoob2006

5 0
3 years ago
1000 millicoulombs of charge passes through a point. The amount of current passing through the point is
Rzqust [24]

The amount of current passing through the point is 1 A

The amount of current passing through the point can be calculated using the formula below.

⇒ Formula:

  • Q = i/t......................... Equation 1

⇒ Where:

  • Q = Charge
  • i = current
  • t = time.

⇒ Make "i" the subject of the equation.

  • i = Qt....................... Equation 2

From the question,

⇒ Given:

  • Q = 1000 millicoulombs = 1 coulombs
  • t = 1 seconds. (Assuming the time is 1 seconds)

⇒ Substitute these values into equation 2

  • i = 1/1
  • i = 1 A.

Hence, The amount of current passing through the point is 1 A.

Learn more about charges here: brainly.com/question/4158552

3 0
2 years ago
I would like help with this physics problem
Darina [25.2K]

(a) This is a freefall problem in disguise - when the ball returns to its original position, it will be going at the same speed but in the opposite direction. So the ball's final velocity is the negative of its initial velocity.

Recall that

v_f=v_i+at

We have v_f=-v_i, so that

-2v_i=at\implies-2\left(8\,\dfrac{\mathrm m}{\mathrm s}\right)=\left(-2\,\dfrac{\mathrm m}{\mathrm s^2}\right)t\implies t=8\,\mathrm s

(b) The speed of the ball at the start and at the end of the roll are the same 8 m/s, so the average speed is also 8 m/s.

(c) The ball's average velocity is 0. Average velocity is given by \dfrac{v_i+v_f}2, and we know that v_f=-v_i.

(d) The position of the ball x_f at time t is given by

x_f=x_i+v_it+\dfrac12at^2

Take the starting position to be the origin, x_i=0. Then after 6 seconds,

x_f=\left(8\,\dfrac{\mathrm m}{\mathrm s}\right)(6\,\mathrm s)+\dfrac12\left(-2\,\dfrac{\mathrm m}{\mathrm s^2}\right)(6\,\mathrm s)^2=42\,\mathrm m

so the ball is 42 m away from where it started.

We're not asked to say in which direction it's moving at this point, but just out of curiosity we can determine that too:

x_f-x_i=\dfrac{v_i+v_f}2t\implies42\,\mathrm m=\dfrac{8\,\frac{\mathrm m}{\mathrm s}+v_f}2(6\,\mathrm s)\implies v_f=6\,\dfrac{\mathrm m}{\mathrm s}

Since the velocity is positive, the ball is still moving up the incline.

8 0
3 years ago
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