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Sergio039 [100]
3 years ago
15

How many liters of carbon dioxide will 0.5 mole of lithium hydroxide (LiOH) absorb? (One mole of any gas occupies 22.4 L under c

ertain conditions of temperature and pressure. Assume those conditions for this question.)
Chemistry
1 answer:
Svet_ta [14]3 years ago
4 0

Answer:

0.5 moles of LiOH will absorb 5.6 L of CO_2

Explanation:

According to law of conservation of mass, the sum of mass on the reactant side must be equal to the sum of mass on product side.

The balanced chemical equation is:

2LiOH+CO_2\rightarrow Li_2CO_3+H_2O

2 moles of LiOH absorb 1 mole of CO_2 i.e. 22.4 Liters at STP

0.5 moles of LiOH absorb

=\frac{22.4}{2}\times {0.5}=5.6Liters

0.5 moles of LiOH will absorb 5.6 L of CO_2

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Chromuate found inside which of the following structures of a eukaryotic cell?
dimulka [17.4K]

Answer:

Chromuates are found in the chromosomes of the eukaryotic cells!!!!

Explanation:

I learned this in 7th grade!!!!

Mark Me Brainliest plzz

4 0
3 years ago
A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.692 kg of water
S_A_V [24]

Answer:

494.49 g of NaCl.

Explanation:

Data obtained from the question include the following:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mass of NaCl =.?

Next, we shall determine the number of mole of NaCl in the solution.

Molality is simply defined as the mole of solute per unit kilogram of solvent. Mathematically, it is expressed as

Molality = mole of solute /Kg of solvent

With the above formula, we can obtain the number of mole NaCl in the solution as follow:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mole of NaCl =..?

Molality = mole of solute /Kg of solvent

3.140 = mole of NaCl /2.692

Cross multiply

Mole of NaCl = 3.140 x 2.692

Mole of NaCl = 8.45288 moles

Finally, we shall covert 8.45288 moles of NaCl to grams. This can be obtained as follow:

Mole of NaCl = 8.45288 moles

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =.?

Mole = mass /Molar mass

8.45288 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 8.45288 × 58.5

Mass of NaCl = 494.49 g.

Therefore, 494.49 g of NaCl are present in the solution.

8 0
3 years ago
a 360mg sample of sugar (molar mass of 180 g/mol) is dissolved in enough water to produce 200mL of solution. after the sugar is
Pie
360 mg / 1000    => 0.36 g

molar mass => 180 /mol

number of moles:

mass of solute / molar mass

0.36 / 180 => 0.002 moles

Volume solution = 200 mL / 1000 => 0.2 L

M = n / V

M = 0.002 / 0.2

M = 0.01 mol/L

hope this helps!
5 0
2 years ago
Indicate the types of forces that are involved between the solute and solvent when forming a homogeneous solution between ch3ch2
Bess [88]
Answer:
            Dispersion Forces are found between n-Pentane (CH₃-CH₂-CH₂-CH₂-CH₃) and n-Hexane (CH₃-CH₂-CH₂-CH₂-CH₂-CH₃).

Explanation:
                   Dispersion Forces are present and developed by those compounds which are non-polar in nature. In given statement n-Pentane and n-Hexane both are non-polar in nature as the electronegativity difference between Hydrogen atoms and Carbon atoms is less than 0.4. 
                   When non-polar molecules approaches each other, a Dipole is induced in one of them, this step is known as Instantaneous Dipole, This generated Dipole on approaching another non-polar molecule induces dipole in it and the process propagates. Hence, creating intermolecular interactions.
8 0
3 years ago
Read 2 more answers
Clear selection
marin [14]

The molarity of the acid given the data from the question is 0.30 M

<h3>Balanced equation </h3>

2HNO₃ + Ba(OH)₂ —> Ba(NO₃)₂ + 2H₂O

From the balanced equation above,

  • The mole ratio of the acid, HNO₃ (nA) = 2
  • The mole ratio of the base, Ba(NO₃)₂ (nB) = 1

<h3>How to determine the molarity of the acid</h3>

From the question given above, the following data were obtained:

  • Volume of acid, HNO₃ (Va) = 39.7 mL
  • Volume of base, Ba(NO₃)₂ (Vb) = 24 mL
  • Molarity of base, Ba(NO₃)₂ (Cb) = 0.250 M
  • Molarity of acid, HNO₃ (Ma) =?

MaVa / MbVb = nA / nB

(Ma × 39.7) / (0.25 × 24) = 2

(Ma × 39.7) / 6 = 2

Cross multiply

Ma × 39.7 = 6 × 2

Ma × 39.7 = 12

Divide both side by 39.7

Ma = 12 / 39.7

Ma = 0.30 M  

Learn more about titration:

brainly.com/question/14356286

#SPJ1

8 0
2 years ago
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