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Sergio039 [100]
2 years ago
15

How many liters of carbon dioxide will 0.5 mole of lithium hydroxide (LiOH) absorb? (One mole of any gas occupies 22.4 L under c

ertain conditions of temperature and pressure. Assume those conditions for this question.)
Chemistry
1 answer:
Svet_ta [14]2 years ago
4 0

Answer:

0.5 moles of LiOH will absorb 5.6 L of CO_2

Explanation:

According to law of conservation of mass, the sum of mass on the reactant side must be equal to the sum of mass on product side.

The balanced chemical equation is:

2LiOH+CO_2\rightarrow Li_2CO_3+H_2O

2 moles of LiOH absorb 1 mole of CO_2 i.e. 22.4 Liters at STP

0.5 moles of LiOH absorb

=\frac{22.4}{2}\times {0.5}=5.6Liters

0.5 moles of LiOH will absorb 5.6 L of CO_2

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3 years ago
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What volume of 6.58M HCI is needed to make 500. mL of 3.00M HCI?
zmey [24]

Answer:

228 mL

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3 0
3 years ago
Consider the reaction. mc014-1.jpg How many grams of methane should be burned in an excess of oxygen at STP to obtain 5.6 L of c
garri49 [273]
The reaction for the combustion of methane can be expressed as follows.
                           CH4 + 2O2 --> CO2 + 2H2O
We solve first for the amount of carbon dioxide in moles by dividing the given volume by 22.4L which is the volume of 1 mole of gas at STP.
                            moles of CO2 = (5.6 L) / (22.4 L/1 mole)
                             moles of CO2 = 0.25 moles
Then, we can see that every mole of carbon dioxide will need 1 mole of methane
                              moles methane = (0.25 moles CO2) x (1 moles O2/1 mole CO2)
                                                    = 0.25 moles CH4
Then, multiply this by the molar mass of methane which is 16 g/mole. Thus, the answer is 4 grams methane. 
5 0
3 years ago
Read 2 more answers
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