Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! Simplify.

Answer 1

Answer:   $\bold{B)\ \dfrac{x-2}{x+1}}$

Step-by-step explanation:

Factor the numerator (top of fraction) and denominator (bottom of fraction).  Then cancel out the common factor.

To factor, find two numbers whose product is the c-value and sum is the b-value.

x² + 5x - 14

              ∧

           -1 +14 = 13

           -2 +7 = 5    this works!

                             So, x² + 5x - 14 = (x - 2)(x + 7)

x² + 8x + 7

              ∧

           1 +7 = 8    this work!

                           So, x² + 8x + 7 = (x + 1)(x + 7)

$\dfrac{x^2+5x-14}{x^2+8x+7}=\dfrac{(x+7)(x-2)}{(x+7)(x+1)}=\dfrac{x-2}{x+1}$

Answer 2

X^2+5x-14 = (x+7)(x-2)
X^2+8x+7=(x+7)(x+1)

(X+7) crosses out

Answer x-2 /x+1