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Margaret [11]
3 years ago
6

What is the percentage by mass of nacl in a saturated solution of sodium chloride at 50 c?

Chemistry
1 answer:
uranmaximum [27]3 years ago
4 0
In this solution we are having two components i.e. NaCl and H₂O. So the %age mass of NaCl is calculated by following formula,

%age mass of NaCl  =  (Mass of NaCl / Mass of NaCl + Mass of H₂O) × 100     ------ (1)

Calculating Mass of NaCl at 50°C;

Solubility of NaCl was searched online and was found 36.69 g / 100 mL of water at 50 °C.

Calculating Mass of 100 mL H₂O at 50°C;

Density of H₂O at 50 °C is 0.988 g/ml, so for 100 mL
As,
                           Density  = Mass / Volume

                           Mass  =  Density × Volume

                           Mass  =  0.988 g/mL × 100 mL

                           Mass  =  98.8 g

Putting Masses of NaCl and H₂O in eq. 1,

              %age mass of NaCl  =  (36.69 g / 36.69 g + 98.8 g) × 100

              %age mass of NaCl  =  (36.69 g / 135.49 g) × 100

              %age mass of NaCl  =  27.07 %
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KiRa [710]

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CaC₂(s) + 2H₂O (l) -----> Ca(OH)₂ (s) + C₂H₂ (g) ​

As we have data of gas ethyne (or acetylene), C₂H₂

We can calculate the moles of acetylene and from this we can estimate the mass of calcium carbide taken

the moles of acetylene will be calculated using ideal gas equation

PV =nRT

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6 0
4 years ago
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o-na [289]

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8 0
4 years ago
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What is the resistance of a 150 W lightbulb connected to a 24 V voltage source?
Luda [366]

Answer:

3.84 Ω

Explanation:

From the question given above, the following data were obtained:

Electrical power (P) = 150 W

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Recall:

V = IR

Divide both side by R

I = V/R

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Where:

P => Electrical power

V => Voltage

I => Current

R => Resistance

With the above formula (i.e P = V²/R), we can calculate resistance as illustrated below:

Electrical power (P) = 150 W

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P = V²/R

150 = 24² / R

150 = 576 / R

Cross multiply

150 × R = 576

Divide both side by 150

R = 576 / 150

R = 3.84 Ω

Thus, the resistance is 3.84 Ω

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3 years ago
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