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3 years ago

What is the percentage by mass of nacl in a saturated solution of sodium chloride at 50 c?

1 answer:

4 0

In this solution we are having two components i.e. NaCl and H₂O. So the %age mass of NaCl is calculated by following formula,

%age mass of NaCl = (Mass of NaCl / Mass of NaCl + Mass of H₂O) × 100 ------ (1)

Calculating Mass of NaCl at 50°C;

Solubility of NaCl was searched online and was found 36.69 g / 100 mL of water at 50 °C.

Calculating Mass of 100 mL H₂O at 50°C;

Density of H₂O at 50 °C is 0.988 g/ml, so for 100 mL
As,
Density = Mass / Volume

Mass = Density × Volume

Mass = 0.988 g/mL × 100 mL

Mass = 98.8 g

Putting Masses of NaCl and H₂O in eq. 1,

%age mass of NaCl = (36.69 g / 36.69 g + 98.8 g) × 100

%age mass of NaCl = (36.69 g / 135.49 g) × 100

%age mass of NaCl = 27.07 %

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199.5 grams unrefined dark crystalline sugar to cups

Dmitry [639]

Answer:

0.9975 cup

Step-by-step explanation:

"Unrefined dark crystalline sugar" is what non-chemists call "brown sugar."

200.0 g brown sugar = 1 cup

199.5 g brown sugar = 199.5× 1/200 .0

199.5 g brown sugar = 0.9975 cup

A standard measuring cup is not capable of this precision and, furthermore, the mass of brown sugar you can get into a cup depends on how tightly you pack it.

Your Mole Day cake will be fine if you use 1 cup of brown sugar as usual.

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3 years ago

What was the velocity over the entire trip? A. -2 B. -1 C. 0 D. 1 E. 2

zhannawk [14.2K]

You’re right its A -2

5 0

3 years ago

MrRissso [65]

Answer:

24.9%

Explanation:

According to this question, mole fraction of NaCl in an aqueous solution is 0.0927. This means that the mole percent of NaCl in the solution is:

0.0927 × 100 = 9.27%

Let's assume that the solution contains water (solvent) + NaCl (solute), hence, the mole fraction of water will be;

100% - 9.27% = 90.73%

THEREFORE, it can be said that, NaCl contains 0.0927moles while H2O contains 9.073moles

N.B: mole = mass/molar mass

Given the Molar Mass

NaCl: 58.44 g/mol

H2O: 18.016 g/mol

For NaCl;

0.0927 = mass/58.44

mass = 0.0927 × 58.44

5.42g

For H2O;

9.073 = mass/18.016

mass = 9.073 × 18.016

= 16.35g

Total mass of solution = 16.35g + 5.42g = 21.77g

Mass percent of NaCl = mass of NaCl/total mass × 100

% mass of NaCl = 5.42g/21.77g × 100

= 0.249 × 100

= 24.9%

5 0

3 years ago

Read 2 more answers

HELP ASAP***

Alchen [17]

D...........................

8 0

4 years ago

Read 2 more answers

The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively.

user100 [1]

Answer:

c 43.38 g

Explanation:

The reaction between MnO2 and HCl can be represented by the following balanced equation:

MnO2 + HCl ---> Cl2 + MnCl2 + H2O

From the balanced equation, the theoretically required molar ratio of MnO2 to HCl is 1:1, therefore the yields would have been expected to be equal.

For the fact that HCl gives a higher yield (65.02g) than MnO2 (60.25g) according to the problem statement, HCl should be in excess, while the limiting reagent should be MnO2 .

Thus, the theoretical yield of Cl2 will be 60.25 g.

By definition, the percentage yield is given by

% Yield = (Actual Yield) / (Theoretical Yield),

This can be simplified to

Actual Yield = % Yield * Theoretical Yield

Plugging in the given values we have

Actual Yield = 72% * 60.25 = 43.38 g

5 0

3 years ago