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solniwko [45]
3 years ago
13

So anyone wanna be a Good Samaritan and help ya girl out

Chemistry
1 answer:
goldenfox [79]3 years ago
8 0

The answer is JESUS BECAUSE HE IS ALWAYS THE ANSWER

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Suppose that in the citric acid cycle, oxalacetate is labeled with 14C in the carboxyl carbon farthest from the keto group. Wher
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All of alpha-ketoglutarate formed in the citric acid cycle would contain the radioactive ^{14}C while none of succinate would contain ^{14}C, and all of carbon dioxide released would contain ^{14}C.

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When oxaloacetate in the citric acid cycle is labeled with ^{14}C in carboxyl carbon atom which is farthest from keto group, alpha ketoglutarate formed from this oxaloactetate has the full radioactive label. In the next step, the carboxylic group (that contains the ^{14}C) is eliminated in the form of the release of the carbon dioxide and succinate is formed. Succinate thus will not have radioactivity. CO_2 released had all the radioactivity.

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