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Montano1993 [528]
3 years ago
15

When conducting an experiment, a scientist should: (a) attempt to test every possibility (b) attempt to control the conditions (

c) place no limits on the investigation (c) proceed without specific goals
Chemistry
2 answers:
skelet666 [1.2K]3 years ago
5 0
B attempt to control the conditions
iragen [17]3 years ago
4 0

Answer : Option B) Attempt to control the conditions.

Explanation : While conducting an experiment, a scientist should always attempt to control the reaction conditions.

If the reaction conditions are not controlled one can lose the expected result or observation that was supposed to be generated from the experiment. Like controlling the given temperature, pressure, addition of catalysts, etc. If these conditions are overlooked one may not achieve the expected results and will not reach to the conclusion.

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What is the number of moles in 10.62 L of H2S gas at STP?
Lina20 [59]

Answer:

0.474 moles

Explanation:

divide 10.62 by 22.4.

7 0
3 years ago
You are asked to make 10 moles of iron (Fe) from iron oxide (fe203) and excess carbon monoxide (CO).
HACTEHA [7]
5 moles.
think about the ratio of moles of iron oxide (Fe2O3) and iron (Fe) in that balanced chemical equation, which is 1:2, respectively. if there are 10 moles of Fe, you would divide that by 2 to get the number of moles of Fe2O3.
6 0
3 years ago
Consider an exceptionally weak acid, HA, with a Ka = 1x10 -20 . You make a 0.1M solution of the salt Na
Vedmedyk [2.9K]

Answer:

pH=13

Explanation:

Hello,

In this case, given the acid, we can suppose a simple dissociation as:

HA\rightleftharpoons H^+ + A^-

Which occurs in aqueous phase, therefore, the law of mass action is written by:

Ka=\frac{[H^+][A^-]}{[HA]}

That in terms of the change x due to the reaction's extent we can write:

1x10^{-20}=\frac{x*x}{0.1M-x}

But we prefer to compute the Kb due to its exceptional weakness:

Kb=\frac{Kw}{Ka}=\frac{1x10^{-14}}{1x10^{-20}}  =1x10^{-6}

Next, the acid dissociation in the presence of the base we have:

Kb=\frac{[OH^-][HA]}{[A^-]}=1x10^{6}=\frac{x*x}{0.1-x}

Whose solution is x=0.0999M which equals the concentration of hydroxyl in the solution, thus we compute the pOH:

pOH=-log([OH^-])=-log(0.0999)=1

Finally, since the maximum scale is 14, we can compute the pH by knowing the pOH:

pH+pOH=14\\\\pH=14-pOH=14-1\\\\pH=13

Regards.

5 0
3 years ago
Read 2 more answers
How many atoms are in c8h8o3?<br> Show your work
Gelneren [198K]

Answer:

im positive that it's 19

8 0
3 years ago
The density of aluminum is 2.7 g/mL if I add a piece of aluminum to a graduated cylinder of water in the water level increases b
viva [34]
The answer would be 5.5g because you have to subtract 8.2 minus 2.7 and you get 5.5g so basically the answer is C.
8 0
3 years ago
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