Which of the following materials will float in water? Cork sugar aluminum iron

20 POINTS IF YOU CAN ANSWER THIS CORRECTLY, PLEASE!

xeze [42]

Answer: a

Explanation: trust me

7 0

3 years ago

What orbitals are used to form the 10 sigma bonds in propane (ch3ch2ch3)? Label each atom with the appropriate hybridization. Dr

SVETLANKA909090 [29]

Mixing of pure orbitals having nearly equal energy to form equal number of completely new orbitals is said to be hybridization.

For the compound, $CH_3CH_2CH_3$ the electronic configuration of the atoms, carbon and hydrogen are:

Carbon (atomic number=6): In ground state= $1s^{2}2s^{2}2p^{2}$

In excited state: $1s^{2}2s^{1}2p^{3}$

Hydrogen (atomic number=1): $1s^{1}$

All the bonds in the compound is single bond( $\sigma$ -bond) that is they are formed by head on collision of the orbitals.

The structure of the compound is shown in the image.

The Carbon-Hydrogen bond is formed by overlapping of s-orbital of hydrogen to p-orbital of carbon.

In order to complete the octet the required number of electrons for carbon is 4 and for hydrogen is 1. So, the electron in $1s^{1}$ of hydrogen will overlap to the 2p^{3}-orbital of carbon.

Thus, the hybridization of Hydrogen is $s$ -hybridization and the hybridization of Carbon is $sp^{3}$ -hybridization.

The hybridization of each atom is shown in the image.

3 0

3 years ago

Are the base pairs always the same?

Monica [59]

No because they can be seperated differently

6 0

3 years ago

Read 2 more answers

Calculate the de broglie wavelength of a subatomic particle that is moving at 351 km/s if its mass is 9.11 Ã 10â31 kg. Î» = hmuh

gregori [183]

The de Broglie wavelength of a subatomic particle is 2.09 nm.

λ = h m v = h

momentum : wherein 'h' is the Plank's steady. This equation pertaining to the momentum of a particle with its wavelength is de Broglie equation and the wavelength calculated the use of this relation is de Broglie wavelength.

Frequency is the ratio of velocity and wavelength in relation to hurry. In evaluation, wavelength refers back to the ratio of velocity and frequency.

Wavelength is the gap between the crests of waves or a person's fashionable mind-set. An instance of wavelength is the gap between the crest of two waves. An instance of wavelength is while you and some other character share the equal standard attitude and might for that reason speak properly.

calculation is given in the image below

de Broglie wavelength λ = h/mv

= (6.626 * 10^-34)/9.1 * 10^-31 *351 *10^3

= 2.07 *10^-9

Hence, = 2.op nm

Learn more about de Broglie wavelength here:-brainly.com/question/16595523

#SPJ4

6 0

2 years ago

When silver nitrate reacts with copper, copper(II) nitrate and silver are produced. The balanced equation for this reaction is:

posledela

The question is incomplete, here is the complete question:

When silver nitrate reacts with copper, copper(II) nitrate and silver are produced. The balanced equation for this reaction is:

$2AgNO_3+Cu\rightarrow Cu(NO_3)_2+2Ag$

Suppose 6 moles of silver nitrate react. The reaction consumes___ moles of copper. The reaction produces __ moles of copper(II) nitrate and __ moles of silver.

Answer: The amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.

Explanation:

We are given:

Moles of silver nitrate = 6 moles

For the given chemical reaction:

$2AgNO_3+Cu\rightarrow Cu(NO_3)_2+2Ag$

For copper metal:

By Stoichiometry of the reaction:

2 moles of silver nitrate reacts with 1 mole of copper metal

So, 6 moles of silver nitrate will react with = $\frac{1}{2}\times 6=3mol$ of copper metal

Moles of copper reacted = 3 moles

For copper(II) nitrate:

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 1 mole of copper(II) nitrate

So, 6 moles of silver nitrate will produce = $\frac{1}{2}\times 6=3mol$ of copper(II) nitrate

Moles of copper(II) nitrate produced = 3 moles

For silver metal:

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 2 moles of silver metal

So, 6 moles of silver nitrate will produce = $\frac{2}{2}\times 6=6mol$ of silver metal

Moles of silver metal produced = 3 moles

Hence, the amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.

6 0

3 years ago