The proper disposal of waste materials is covered under osha 1926.252 in

1 answer:

8 0

1962.252(a) whenever the material is dropped from 20feet to any poiny lying outside the exterior wall of building, an enclosed chute of wood, or equivalent material. For the purpose of paragraph, an enclose chute is a slide, closed in all sides, through which material is placed from high plac eto lower one. 1962.252(b) when the disposal is dropped through holes in the floor without the use of chute, the area onto which the material is dropped shall be completely enclosed with barricades not less than 42 inch high and not less than 6 feet back from the projected edge of of the opening valve. signs warning of hazards of falling material shall be posted at each level. 1962.252(c) All scrap lumper, waste material, and rubbish shall be removed from the immediate work area as the work progresses. 1962.252(d) Disposal of waste material or debris by burning shall comply with local fire regulation 1962.252(e) All sovent waste, oily rags, and flammable liquid should be kept in fire resistant covered container until removed from work site.

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5.2 X 1026 molecules of CH4

olya-2409 [2.1K]

<h3 /><h3>Answer above </h3>

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2 years ago

What would be the total volume of the new solution when it is changed from 0.2 M to 0.04 M?

34kurt

The question is incomplete.

You need two additional data:

1) the original volume
2) what solution you added to change the volume.

This is a molarity problem, so remember molarity definition and formula:

M = n / V in liters: number of moles per liter of solution

To give you the key to answer this kind of questions, supppose the original volumen was 1 ml and that you added only water (solvent).

The original solution was:

V= 1 ml
M = 0.2 M

Using the formula for molarity, M = n / V

n = M×V = 0.2 M × (1 / 10000)l = 0.0002 moles

For the final solution:

n = 0.0002 moles
M = 0.04

From M = n / V ⇒ V = n / M = 0.002 moles / 0.04 M = 0.05 l

Change to ml ⇒ 0.05 l × 1000 ml / l = 50 ml. This would be the answer for the hypothetical problem that I assumed for you.

I hope this gives you all the cues you need to answer similar problems about molarity.

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3 years ago

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Could someone please tell show me steps to solve this, I am so confused.

jonny [76]

And this is y I should of paid attention in that one science class in middle school that taught this...

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3 years ago

Which compound contains both ionic and covalent bonds? 1. ki 2. cacl2 3. ch2br2 4. nacn?

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NaCn contains an Na+ ion and a CN- negative ion, so it has an ionic bond. The CN ion is formed by a covalent bond of the carbon and nitrogen, so it also has a covalent bond. Therefore, the answer is NaCN.

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